Pluto is 39.5 AU from the sun on average. How long is one year on Pluto?

Calculate the number of moles of gas present in the sealed container at a

aliina [53]

Here volume of gas is not given so question is solved assuming volume as 1 L.

The number of moles of 1 L gas present in the sealed container at a

pressure of 125 kPa at 25 degrees Celsius is 0.0067 moles.

The ideal gas law equation can be written as

PV = nR T

Here

P is the pressure of the gas in atm

V is the volume it occupies in L

n is the number of moles of gas present in the sample

R is the universal gas constant, equal to 0.0821 atm L/ mol K

T is the absolute temperature of the gas in Kelvin

Now, it's important to realize that the units you have for the volume, pressure, and temperature of the gas must match the unit used in the expression of the universal gas constant.

So

P = 125 kPa

1 atm = 760 kPa

P = 125/760 = 0.1644 atm

T = 25 degree celsius = 25 +273 = 298 K

Taking V = 1 L

So

n = PV/RT

n = 0.1644 x 1 / 0.0821 x 298

n = 0.0067 moles

To learn more about the ideal gas law, please click on the link brainly.com/question/128737528

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8 0

2 years ago

Where might someone with a pharmaceutical manufacturing career work?

klemol [59]

Answer: People with careers in pharmaceutical manufacturing can expect to work in: research laboratories or manufacturing plants, and to maintain work hours during the day.

Explanation:

8 0

3 years ago

The planet Uranus has a radius of 25,360 km and a surface acceleration due to gravity of 9.0 m/s^2 at its poles. Its moon Mirand

AlexFokin [52]

Answer:

$8.67791\times 10^{25}\ kg$

$0.34589\ m/s^2$

$0.07903\ m/s^2$

Explanation:

M = Mass of Uranus

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Uranus = 25360 km

h = Altitude = 104000 km

$r_m$ = Radius of Miranda = 236 km

m = Mass of Miranda = $6.6\times 10^{19}\ kg$

Acceleration due to gravity is given by

$g=\dfrac{GM}{r^2}\\\Rightarrow M=\dfrac{gr^2}{G}\\\Rightarrow M=\dfrac{9\times 25360000^2}{6.67\times 10^{-11}}\\\Rightarrow M=8.67791\times 10^{25}\ kg$

The mass of Uranus is $8.67791\times 10^{25}\ kg$

Acceleration is given by

$a_m=\dfrac{GM}{(r+h)^2}\\\Rightarrow a_m=\dfrac{6.67\times 10^{-11}\times 8.67791\times 10^{25}}{(25360000+104000000)^2}\\\Rightarrow a_m=0.34589\ m/s^2$

Miranda's acceleration due to its orbital motion about Uranus is $0.34589\ m/s^2$

On Miranda

$g_m=\dfrac{Gm}{r_m^2}\\\Rightarrow g_m=\dfrac{6.67\times 10^{-11}\times 6.6\times 10^{19}}{236000^2}\\\Rightarrow g_m=0.07903\ m/s^2$

Acceleration due to Miranda's gravity at the surface of Miranda is $0.07903\ m/s^2$

No, both the objects will fall towards Uranus. Also, they are not stationary.

6 0

3 years ago

A thin, rectangular sheet of metal has mass M and sides of length a and b. Find the moment of inertia of this sheet about an axi

Lubov Fominskaja [6]

Answer:

The moment of inertia is $I=\frac{M}{12} a^{2}$

Explanation:

The moment of inertia is equal:

$I=\int\limits^a_b {r^{2} } \, dm$

If r is $-\frac{a}{2}$

and $dm=\frac{M}{a} dr$

$I=\int\limits^a_b {r^{2}\frac{M}{a} } \, dr\\a=\frac{a}{2} \\b=-\frac{a}{2}$

$I=\frac{M}{a} \int\limits^a_b {r^{2} } \, dr\\\\I=\frac{M}{a} (\frac{M}{3} )_{b}^{a}\\ I=\frac{M}{3a} (\frac{a^{3} }{8} +\frac{a^{3} }{8} )\\I=\frac{M}{12} a^{2}$

7 0

4 years ago

Which of the following is a source of thermal energy that is absorbed by Earth's atmosphere?

Mazyrski [523]

Answer:

100% of the energy entering earth's atmosphere comes from the sun. ~50% of the incoming energy is absorbed by the earth's surface i.e. the land and oceans.

8 0

3 years ago