Answer:
Perimeter of figure = 36.3
Step-by-step explanation:
We'll begin by calculating the perimeter of the rectangle. This can be obtained as follow:
Length (L) = 9
Width (W = 4
Perimeter of rectangle (Pᵣ) =?
Pᵣ = 2(L + W)
Pᵣ = 2(9 + 4)
Pᵣ = 2(13)
Pᵣ = 26
Next, we shall determine the perimeter of semi circle. This can be obtained as follow:
Diameter (d) = 4
Pi (π) = 3.14
Perimeter of semi circle (Pₛ) =?
Pₛ = ½(πd) + d
Pₛ = ½(3.14 × 4) + 4
Pₛ = ½(12.56) + 4
Pₛ = 6.28 + 4
Pₛ = 10.28
Finally, we shall determine the perimeter of the figure. This can be obtained as follow:
Perimeter of rectangle (Pᵣ) = 26
Perimeter of semi circle (Pₛ) = 10.28
Perimeter of figure =?
Perimeter of figure = Pᵣ + Pₛ
Perimeter of figure = 26 + 10.28
Perimeter of figure = 36.28 ≈ 36.3
Answer:The roots of any quadratic equation is given by: x = [-b +/- sqrt(-b^2 - 4ac)]/2a. Write down the quadratic in the form of ax^2 + bx + c = 0. If the equation is in the form y = ax^2 + bx +c, simply replace the y with 0. This is done because the roots of the equation are the values where the y axis is equal to 0.
Step-by-step explanation:
x=20 and y=4 ......... ....... .............. ....
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Answer:
Step-by-step explanation:
y +7=-2/3(x + 6) can be written as y=-2/3 x -4 -7= -2/3 x -11
From this equation you can have the points where the line crosses the 'x' axis and the 'y' axis
One of which is obtained by doing y=0 and solving for x, it gives the 'x' axis crossing point
The other is obtained by doing x=0 and solving for y, it gives the 'y' axis crossing point