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vlabodo [156]
2 years ago
8

Determine the slope-intercept form of the equation of the line parallel to y = -4/3 x + 11 that passes through the point (–6, 2)

.
y= _____x + _____

Please Help!

Mathematics
1 answer:
MatroZZZ [7]2 years ago
7 0
I've attached working :)

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A

Step-by-step explanation:

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Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ
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Answer: 5x-3y=44

Step-by-step explanation:

We know that , the equation of a line that passes through (a,b) and (c,d) is given by :_

(y-b)=\dfrac{d-b}{c-a}(x-a)

Standard form of equation of line = Ax+By=C

Given points =  (7, -3) and (4, -8)

Then, the equation of a line that passes through the points . (7, -3) and (4, -8) is given by -

(y-(-3))=\dfrac{-8-(-3)}{4-7}(x-7)

(y+3)=\dfrac{-8+3}{-3}(x-7)   [∵ (-)(-)=(+)]

(y+3)=\dfrac{-5}{-3}(x-7)

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44=5x-3y

Or 5x-3y=44

Hence, the required equation :-5x-3y=44

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3 years ago
6x-12y=36 <br> Converting from standard form to slope intercept form
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Slope intercept form is y=mx+b
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