To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).
Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.
The power rule for derivatives is ![\frac{d}{dx} [x^{n} ] =nx^{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bx%5E%7Bn%7D%20%5D%20%3Dnx%5E%7Bn-1%7D)
. In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.
f'(x) = 
(2x⁴)
f'(x) = 2(4)x³
f'(x) = 8x³
Now, to find f'(3), plug 3 into your derivative.
f'(3) = 8(3)³
f'(3) = 216
<h3>Answer:</h3>
f'(3) = 216
(4,9) is in quarter I and (4,-9) is in quarter IV of the graph. (4,-9) is the point (4,9) reflected over the x-axis. they are similar bc both have 4 as their x coordinate.
Answer:
radius
Step-by-step explanation:
Answer:
m<1 = 105°
m<2 = 75°
very simple explanation:
a and b are perpendicular. line t intersects these perpendicular lines. the given 75° is, in short, an intersect of a line, which is 180°. 75-180=105. angles 1 and 2 are duplicates of what is shown
I’m not sure try again and tell me
