Answer/ Explanation:
a. The genotype of a homozygous white eyed long winged female would be Vg+Vg+XrXr. We denote the white allele as recessive (r) because the XY male only has one copy and yet has red eyes, so the red eye trait (R) must be dominant. A homozygous red eyed vestigial winged male would have be VgVgXRY. The possible gametes for the female are Vg+Xr only. For the male, the possible gametes are VgXR or VgY
The attached punnett square shows the results of the cross. The females will all be Vg+VgXRXr. The males will all be Vg+VgXRY (must inherit Y from father). That means they will all have normal length wings, the males will have white eyes and the females will have red eyes.
b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr
, Vg+Y
, VgXr
, VgY
. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.
c. F1 cross back to the mother would be Vg+VgXRY x Vg+Vg+XrXr. The genotypes are shown in the attached punnet square. The offspring will all be long-winged with white eyes. The F1 to the father would be Vg+VgXRXr x VgVgXRY. The ratio would be 3:3:1:1 long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye
Answer:
Meiosis is a reduction division of diploid cells.(2n) Chromosomes numbers are reduced with each successive division stages of meiosis 1 and 2, to haploid(n).
Cats have 38 diploid somatic (body)chromosome (2n) in the somatic cells and are reduced to 19 new varied haploid cells (n) of chromosomes in the gametes.
In cats, as in other mammals, during spermatogenesis in (seminiferous tublule of testis) and oegensis(in the ovaries);<u>meiotic reduction division</u> reduced the diploid somatic chromosomes to haploid chromosomes in sex gametes.
Therefore 38 chromosomes will be in the somatic chromosomes, while the sex gametes, with double-helical molecules of DNA, at the end of meiosis II will have 19 chromosomes, half of the somatic chromosomes.
Explanation:
D- During interphase, when the cell is not dividing, chromatin is less tightly packed compared to our chromosomes, which allows transcription to occur.
Answer:
As chlorine has 7 valence electrons, it tends to form bonds to gain one electron (to get a full valence shell of 8).On the other hand, potassium has one valence electron, so it tends to lose this electron to other atoms (and
become a cation)
