What function has the same y intercept as the function y=2/x -3

Mathematics

1 answer:

Tema [17]3 years ago

3 0

$The \: answer \: is \: none, \: because \: the \: function \: y = \frac{2}{x} - 3 \: doesn't \: have \: a \: y \: intercept.$

You might be interested in

So. This question is very troubling. It’s

slega [8]

Answer:

2 because negatives arent greater than whole numbers

3 0

3 years ago

PLEASE ANSWER ASAP: Last year, Springfield Middle School had 526 students. This year, it has 496 students. To the NEAREST TENTH,

GaryK [48]

Answer:

5.7 is the answer good sir your welcome

3 0

2 years ago

Read 2 more answers

A parachutist's rate during a free fall reaches 165 feet per second. What is this rate in meters per second? At this rate, how m

Fiesta28 [93]

Assuming that:

1
m
=
3.3
f
t
1m=3.3ft

We can make the conversion from feet per second to meters per second with this procedure:

(
165

f
t
s
)
(
1

m
3.3

f
t
)
=
50

m
s
(165
s
ft

)(
3.3 ft
1 m

)=50
s
m

Let
x
x be the amount of meters the parachutist will fall during 15 seconds of free fall

Having that in 1 second the parachutist falls 50 meters, we can calculate
x
x :

x
=
(
50

m
s
)
(
15

s
)

x=(50
s
m

)(15 s)

x=750 m

3 0

3 years ago

Find the area of the parallelogram that has adjacent sides Bold u equals Bold i minus 2 Bold j plus 2 Bold kand Bold v equals 3

Mice21 [21]

Answer:

The area of the parallelogram is $A=\sqrt{26}$ .

Step-by-step explanation:

Let's rewrite these two vectors:

$u=i-2j+2k$

$v=0i+3j-k$

Let's recall that the area of the parallelogram is the magnitude of the cross product between these vectors.

We can use the Determinant method to find it.

$u \times v=\left[\begin{array}{ccc}i&j&k\\1&-2&2\\0&3&-1\end{array}\right] = i((-2)*(-1)-2*3)-j(1*(-1)-2*0)+k(1*3-(-2)*0)=i(2-6)-j(-1)+k(3)=-4i+j+3k$