Ask question

Ask question

All categories

3 years ago

7

The population of a city in 2005 was 18,000. By 2010, the city's population had grown to 32,800. If the population growth follow

s a linear model, what is the projected population for 2015?

1 answer:

kotykmax [81]3 years ago

3 0

Answer:

The projected population for 2015 is around 83,600 people.

Step-by-step explanation:

If between 2005 and 2010, the population grew by 32,800 people, and the model of this problem is linear. Then that means in another 5 years, another 32,800 people would populate the area. Hopefully this makes sense!

You might be interested in

Consider the following graph.

Fed [463]

Cheryl drove at a speed of 65 mph for 1 minute, drove at a constant speed for 5.5 minutes, and then drove at a speed of 45 mph for 2.5 minutes.Option C is correct.

<h3>What is a graph?</h3>

A diagram depicting the relationship between two or more variables, each measured along with one of a pair of axes at right angles.

Cheryl traveled at a steady pace for 5.5 minutes, then 45 mph for 2.5 minutes after traveling at 65 mph for a minute.

Statement C best describes Cheryl's commute.

Hence option C is correct.

To learn more about the graph, refer to the link;

brainly.com/question/14375099

#SPJ1

4 0

2 years ago

The figures below are similar, explain what you know about the sides.

dem82 [27]

That they are the exact same shape. Some of the sides will be longer and shorter than the other figure, but same shape.

8 0

3 years ago

Given the preimage and image,find the dilation scale factor.

Oliga [24]

Answer:

The dilation scale factor is $\frac{1}{2}$ .

Step-by-step explanation:

The image is the dilated form of its preimage if and only if the following conditions are observed:

1) $K' = \alpha_{1} \cdot K$

2) $T' = \alpha_{2} \cdot T$

3) $P' = \alpha_{3} \cdot P$

4) $J' = \alpha_{4} \cdot J$

5) $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$

If we know that $K = (2, 0)$ , $K' = (1, 0)$ , $T = (3, 0)$ , $T' = (1.5,0)$ , $P = (1, 5)$ , $P' = (0.5, 2.5)$ , $J = (0, 3)$ and $J' = (0, 1.5)$ , then the coefficients are, respectively:

$\alpha_{1} = \frac{1}{2}$ , $\alpha_{2} = \frac{1}{2}$ , $\alpha_{3} = \frac{1}{2}$ , $\alpha_{4} = \frac{1}{2}$

As $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$ , we conclude that the dilation scale factor applied in the preimage is equal to $\frac{1}{2}$ .

7 0

3 years ago

alexdok [17]

Answer:

Rx)=1/3x^2

Step-by-step explanation:

A horizontal stretch is simply making the parabola of the parent function wider, it's kind of like changing the slope of a line to make it less steep.

In the graph, the red line is the parent function and the blue line is the horizontally stretched function. See how the blue line appears to be stretched (horizontally).

4 0

3 years ago

A market research firm knows from historical data that telephone surveys have a 36% response rate. In a random sample of 280 tel

Rasek [7]

Answer:

0.6604

Step-by-step explanation:

Given that a market research firm knows from historical data that telephone surveys have a 36% response rate.

Sample size of random sample = 280

We know for samples randomly drawn of large size sample proportion follows a normal distribution with mean= sample proportin and std error

= $\sqrt{\frac{pq}{n} }$

Substitute p = 0.36 and q = 1-0.36= 0.64

p follows N with mean = 0.36 and std dev = $\sqrt{\frac{0.36*0.64}{\sqrt{280} } } \\=0.0287$

Using normal distribution values we can find\

$P(33.5p.c. < p < 39pc)\\= P(0.335$

3 0

3 years ago

Read 2 more answers