What quantities determine how quickly a wave travels along a string? Choose all that apply..a)Mass of the stringb)Length of the
1 answer:
Answer:
a)Mass of the string
b)Length of the string
c)Tension in the string
d)Linear density of the string
Explanation:
The speed of a wave on a string is given by:
where
T is the tension in the string
m is the mass of the string
L is the length of the string
m/L is the linear density of the string
Looking at the formula, we notice that the speed of the wave, v, depends on all the following quantities:
a)Mass of the string
b)Length of the string
c)Tension in the string
d)Linear density of the string
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Answer:
A) a frictional force is acting on it
Explanation:
The crate is sliding down the inclined ramp at constant velocity: constant velocity means zero acceleration, a = 0. According to Newton's second law:
F = ma
this also means that the net force acting along the direction of the slope is zero.
Without frictional force, there would be only one force acting along this direction: the component of the weight of the crane parallel to the slope, acting downward:
where is the angle of the incline. Therefore, the net force along this direction would not be zero. In order to have a net force of zero, there must be another force acting upward on the crate: and the only force that is possibly acting on the crate against its direction of motion is the frictional force, whose magnitude must be equal to
, in order to produce a net force of zero (and therefore, a zero acceleration).
Answer:
The unmarked police car needs approximately 71.082 seconds to overtake the speeder.
Explanation:
Let suppose that speeder travels at constant velocity, whereas the unmarked police car accelerates at constant rate. In this case, we need to determine the instant when the police car overtakes the speeder. First, we construct a system of equations:
Unmarked police car
(1)
Speeder
(2)
Where:
- Initial position, measured in meters.
- Final position, measured in meters.
,
- Initial velocities of the unmarked police car and the speeder, measured in meters per second.
- Acceleration of the unmarked police car, measured in meters per square second.
- Time, measured in seconds.
- Initial instant for the unmarked police car, measured in seconds.
By equalizing (1) and (2), we expand and simplify the resulting expression:
If we know that ,
,
and
, then we solve the resulting second order polynomial:
(3)
,
Please notice that second root is due to error margin for approximations in coefficients. The required solution is the first root.
The unmarked police car needs approximately 71.082 seconds to overtake the speeder.