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Rudik [331]
3 years ago
9

Which of the following would likely be the best reflector of heat energy

Physics
2 answers:
olga55 [171]3 years ago
8 0
B becuase light reflects from pale smooth colours like white, but black absorbs it
mr Goodwill [35]3 years ago
6 0
Ok so B would be the best surface to reflect heat energy as it's polished and does not disturb the wave of energy like the others would. Also in therms of colour it's better because it's a lighter colour than navy ( the darker colour of the spectrum ). This matters as darker colours absorb light where light colour reflect it.
Hope this helps :).

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Can a vector be shorter than one of its components
Sauron [17]
It can never be shorter than a component - magnitude of avector is the square root of the sum of the components squared, and a square function never produces a negative number. However, it can be the same size as its component, if that component is the only one
3 0
4 years ago
A bullet is fired at a speed of 15 m/s from the edge of a cliff. The bullet strikes the ground 65 m from a height H. Find the fi
svet-max [94.6K]

Answer:

v=38.73m/s

Explanation:

u=15m/s

v =?

s=65m

g=9.81

v²=u²+2×g×s

v²=15²+2×9.81×65=1500.3

v=38.73m/s

8 0
3 years ago
A 36N force applied vertically upwards on an object causes it to accelerate at 2.0m/s2. What is the object's mass?
Natalija [7]

Force  =  mass  * acceleration

mass = Force/acceleration

        = 36/2

mass = 18 kg

7 0
3 years ago
A step-up transformer has 50 turns on its primary coil and 2000 turns on its secondary
ryzh [129]

Answer:

Vs= 6000 v

Ip=9.6 A

Explanation:

Ns/Np = Vs/Vp

2000/50 = Vs/150

40 x 150 = Vs

Vs= 6000 v

Vs/Vp=Ip/Is

6000/150=Ip /0.24

Ip=9.6 A

7 0
3 years ago
If during the submerged weighing procedure air bubbles were to adhere to the object, how would the experimental results be affec
Mazyrski [523]

Answer:

see from this analysis, the apparent weight of the body is lower due to the push created by the air brujuleas

Explanation:

We will propose this exercise using Archimedes' principle, which establishes that the thrust on a body is equal to the volume of the desalted liquid.

          B = ρ g V

The weight of a submerged body is the net force between the weight and the thrust

          F_net = W - B

we can write the weight as a function of the density

          ρ_body = m / V

         m =  ρ_body V

         W = mg

         W =  ρ _body g V

we substitute

         F_net= ( ρ_body -  ρ _fluid) g V

In general this force is directed downwards, we can call this value the apparent weight of the body. This is the weight of the submerged body.

          W_aparente = ( ρ_body -  ρ _fluid) g V

If some air bubbles formed in this body, the net force of these bubbles is

         F_net ’= #_bubbles ( ρ_fluido -  ρ_air) g V’

this force is directed upwards

whereby the measured force is

         F = W_aparente - F_air  

           

As we can see from this analysis, the apparent weight of the body is lower due to the push created by the air brujuleas

6 0
3 years ago
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