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sattari [20]
4 years ago
5

A packing crate slides down an inclined ramp at constant velocity. Thus we can deduce thatA) a frictional force is acting on itb

) a net downward force is acting on itc) A net upward force is acting on itD) it is not acted on by appreciable normal forcee) it is not acted on by appreciable gravitational force
Physics
1 answer:
torisob [31]4 years ago
8 0

Answer:

A) a frictional force is acting on it

Explanation:

The crate is sliding down the inclined ramp at constant velocity: constant velocity means zero acceleration, a = 0. According to Newton's second law:

F = ma

this also means that the net force acting along the direction of the slope is zero.

Without frictional force, there would be only one force acting along this direction: the component of the weight of the crane parallel to the slope, acting downward:

W_p = mg sin \theta

where \theta is the angle of the incline. Therefore, the net force along this direction would not be zero. In order to have a net force of zero, there must be another force acting upward on the crate: and the only force that is possibly acting on the crate against its direction of motion is the frictional force, whose magnitude must be equal to W_p, in order to produce a net force of zero (and therefore, a zero acceleration).

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In a double-slit experiment, the third-order maximum for light of wavelength 490 nm is located 15 mm from the central bright spo
jeka94

Answer:

The distance from the central bright spot are 156.8\times10^{-3}\ mm and 142.9\times10^{-3}\ mm.

Explanation:

Given that,

Wavelength = 490 nm

Distance y= 15 mm

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Using formula of distance

y= \dfrac{m\lambda L}{d}

d=\dfrac{m\lambda L}{y}

Put the value into the formula

d=\dfrac{3\times490\times10^{-9}\times1.6}{15\times10^{-3}}

d=156.8\times10^{-6}\ m

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We need to calculate the distance from the central bright spot for new wavelength

Using formula of distance

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d=142.9\times10^{-6} m

d=142.9\times10^{-3}\ mm

Hence, The distance from the central bright spot are 156.8\times10^{-3}\ mm and 142.9\times10^{-3}\ mm.

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3 years ago
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