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Oksana_A [137]
3 years ago
14

Which of these molecular electron configurations describe an excited state?

Chemistry
2 answers:
kherson [118]3 years ago
4 0
<span>We have ground strate configurations of electrons,if electrons are filled in order of increasing energy. When there are electrons are in higher orbitals, we have an atom in an excited state. B, and C are excited states. In B, 2 electrons can fit in the 4s orbital, and that should fill fully before the 4p orbitals. In C, the same is true for 5s and 5p In D, this is not an excited state because 4s fills before 3d</span>
REY [17]3 years ago
3 0

Answer:

See attachment with this answer

Explanation:

Electronic configuration:

Definition:

The electronic configuration is defined as the arrangement of electrons in atomic or molecular orbitals.

Electronic configuration is used for:

The electronic configuration describes the ground state of the orbitals present in an atom or also to describe the ionized state of an atom.

Three principles of electronic configuration:

The electronic configuration is based on three principles Hund's Rule, Aufbau's Principle, and Pauli-exclusion principle.

Excited-state of Atom:

The excited state in an atom is the state in which electron revolving around orbitals have a higher energy state than the ground state.

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For a 0-order response, the mathematical expression that may be employed to determine the half of life is: t1/2 = [R]0/2k. For a first-order reaction, the half of-existence is given by: t1/2 = zero.693/ok. For a 2d-order response, the method for the half-life of the response is: 1/okay[R]0

The 1/2-life of a response (t1/2), is the quantity of time needed for a reactant concentration to lower via half of compared to its initial awareness. Its software is used in chemistry and medicine to are expecting the awareness of a substance over time

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1 year ago
Calculate the bond energy per mole for breaking all the bonds in methane, CH4. Express your answer to four significant figures a
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3 years ago
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Consider the reaction: 2NO(g) + 2H2(g) → N2(g) + 2H2O(g) A suggested mechanism for this reaction follows: (1) NO(g) + NO(g) → N2
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Hello. This question is incomplete. The full question is:

"Consider the following reaction.  2NO(g) + 2H2(g) → N2(g) + 2H2O(g)

A proposed reaction mechanism is:  NO(g) + NO(g) N2O2(g) fast  N2O2(g) + H2(g) → N2O(g) + H2O(g) slow  N2O(g) + H2(g) → N2(g) + H2O(g) fast

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A. rate = k[H2] [NO]2

Explanation:

A reaction mechanism is a term used to describe a set of phases that make up a chemical reaction. In these phases a detailed sequence of each step is shown, composed of several complementary reactions, which occur during a chemical reaction.

These mechanisms are directly related to chemical kinetics and allow changes in reaction rates to be observed in advance.

Reaction rate, on the other hand, refers to the speed at which chemical reactions occur.

Based on this, we can observe through the reaction mechanism shown in the question above, that the action "k [H2] [NO] 2" would have no changes in the reaction rate.

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<em>Basic</em><em> </em><em>radical</em><em> </em>

<em> The ion formed after the removal of hydroxide ion (OH−) from a base is known as basic radical.</em>

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