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3 years ago

Which of these molecular electron configurations describe an excited state?

Chemistry

2 answers:

kherson [118]3 years ago

4 0

We have ground strate configurations of electrons,if electrons are filled in order of increasing energy. When there are electrons are in higher orbitals, we have an atom in an excited state. B, and C are excited states. In B, 2 electrons can fit in the 4s orbital, and that should fill fully before the 4p orbitals. In C, the same is true for 5s and 5p In D, this is not an excited state because 4s fills before 3d

REY [17]3 years ago

3 0

Answer:

See attachment with this answer

Explanation:

Electronic configuration:

Definition:

The electronic configuration is defined as the arrangement of electrons in atomic or molecular orbitals.

Electronic configuration is used for:

The electronic configuration describes the ground state of the orbitals present in an atom or also to describe the ionized state of an atom.

Three principles of electronic configuration:

The electronic configuration is based on three principles Hund's Rule, Aufbau's Principle, and Pauli-exclusion principle.

Excited-state of Atom:

The excited state in an atom is the state in which electron revolving around orbitals have a higher energy state than the ground state.

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A student calculates that the volume of his textbook is 991.880 cm3. what is the volume written with 3 significant figures?

k0ka [10]

The volume of the textbook calculated by the student written to 3 significant figures is 992cm³

According to this question, a student calculates the volume of his textbook and arrived at an answer of 991.880 cm³.

To round up this digit to 3 significant figures, which means that only 3 significant numbers should appear in the answer.

To do this, the number after the third number is 8, which means we can round up the value of 1 to 2. Hence, the volume of the textbook calculated by the student is 992cm³ in 3 s.f.

Learn more at: brainly.com/question/16563962?referrer=searchResults

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2 years ago

The normal freezing point of a certain liquid

stepladder [879]

Answer : The molal freezing point depression constant of X is $4.12^oC/m$

Explanation : Given,

Mass of urea (solute) = 5.90 g

Mass of X liquid (solvent) = 450.0 g

Molar mass of urea = 60 g/mole

Formula used :

$\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}\times 1000}{\text{Molar mass of urea}\times \text{Mass of X liquid}}$

where,

$\Delta T_f$ = change in freezing point

$\Delta T_s$ = freezing point of solution = $-0.5^oC$

$\Delta T^o$ = freezing point of liquid X= $0.4^oC$

i = Van't Hoff factor = 1 (for non-electrolyte)

$K_f$ = molal freezing point depression constant of X = ?

m = molality

Now put all the given values in this formula, we get

$[0.4-(-0.5)]^oC=1\times k_f\times \frac{5.90g\times 1000}{60g/mol\times 450.0g}$

$k_f=4.12^oC/m$

Therefore, the molal freezing point depression constant of X is $4.12^oC/m$

4 0

3 years ago

Swimming pool structures and structural _____ [680.26(B)(1) and (B)(2)] shall not be used as a grounding electrode.

leonid [27]

A grounding electrode is any object that directly links to the earth. They are most times used to divert electricity from the elements.

Swimming pool structures and structural reinforcing steel. 250.52(B)(3), [680.26(B)(1), and (B)(2)] shall not be used as a grounding electrode.

In code 250.52(B)(3) it is clearly specified that the bonding grid and reinforcing steel that is related to a pool should not be used as grounding electrodes.

This is essential because when a metal that lies beneath a swimming pool is used as a grounding electrode, current from nearby electrical systems can be introduced into the pool.

This could cause the electrocution of anybody in the swimming pool at that time.

Learn more here:

brainly.com/question/14681208

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2 years ago

A lead mass is heated and placed in a foam cup calorimeter containing 50.0 ml of water at 18.0°c. the water reaches a temperatur

garri49 [273]

Heat gained or loss in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)

When two objects are in contact, it should be that the heat lost is equal to what is gained by the other. So, the heat released by the lead is equal to the heat that is absorbed by the water.

Heat = mC(T2-T1) = 50.0 mL (1.00 g/mL) (4.18 J/g °C) (20 °C - 18 °C) = 418 J

8 0

3 years ago

Read 2 more answers

What was one main point of Dalton's atomic theory?

sweet-ann [11.9K]

Answer:

C. That atoms made up the smallest form of matter

Explanation:

The crux of the Dalton's atomic theory is that atoms are the smallest form of matter. He propositioned that atoms is an indivisible particle and beyond an atom, no form of matter exists.

Series of discoveries through time have greatly shaped the Dalton's atomic theory. The discovery of cathode rays by J.J Thomson in 1897 opened up the atom. Atoms were now seen to be made up of some negatively charged particles. Ernest Rutherford through his gold foil experiment proposed the nuclear model of the atom.

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2 years ago