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Serggg [28]
3 years ago
9

How to write generic word equation and a chemical equation for the reaction that occurs when an anhydrous salt is placed in wate

r (hydrated)?
Chemistry
1 answer:
Oksana_A [137]3 years ago
3 0
The generic solution of the reaction that occurs would be writen as water + anhydrous salt  = hydrated salt 
chemical equation  would look like this xH2O +AB = AB.xH2O
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2<br> CuCl2 +4KI -&gt; 2 Cul + 4 KCI + 12
Amanda [17]

Answer:

Explanation:

This is an example of a limiting reactant question, and is very common as a general chemistry problem.

We first see the balanced equation, that is:

2CuCl2+4KI→2CuI+4KCl+I2

We first need to find the limiting reactant

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Copper(II) chloride has a molar mass of

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Potassium iodide has a molar mass of

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if it wrong i am sorry

5 0
3 years ago
A helium-filled weather balloon has a volume of 793 L at 16.9°C and 759 mmHg. It is released and rises to an altitude of 4.05 km
mariarad [96]
<h3>Answer:</h3>

1082.96 L

<h3>Explanation:</h3>

We are given;

  • Initial volume of helium gas, V1 = 793 L
  • Initial temperature, T1 = 16.9°C

            But, K = °C + 273.15

  • Thus, initial temperature, T1 is 290.05 K
  • Initial pressure, P1 = 759 mmHg
  • New pressure at 4.05 km, P2 = 537 mmHg
  • New temperature at 4.05 km, T2 = 7.1 °C

                                                             = 280.25 K

Assuming we are required to calculate the new volume at the height of 4.05 km

We are going to use the combined gas law.

  • According to the combined gas law;

\frac{P1V1}{T1}=\frac{P2V2}{T2}

  • Rearranging the formula;

V2=\frac{P1V1T2}{P2T1}

V2=\frac{(759mmHg)(793L)(280.25K)}{(537mmHg)(290.05K)}

V2=1082.96L

Therefore, the new volume of the balloon at the height of 4.05 km is 1082.96 L

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