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gayaneshka [121]
2 years ago
10

Name the method that used to separate the components of petroleum oil.

Chemistry
1 answer:
maw [93]2 years ago
6 0

Answer:

fractional distillation

Explanation:

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Consider each of the following molecules in turn: (a) dimethyl ether, (CH3)2O; (b) trimethylamine, (CH3)3N; (c) trimethylboron,
Luden [163]

Answer:

Consider each of the following molecules in turn: (a) dimethyl ether, (CH3)2O; (b) trimethylamine, (CH3)3N; (c) trimethylboron, (CH3)3B; and (d) carbon dioxide (CO2). Describe the hybridization state of the central atom (i.e., O, N, B, or C) of each molecule, tell what bond angles you would expect at the central atom, and state whether the molecule would have a dipole moment.

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3 years ago
A 4.7-L sealed bottle containing 0.33 g of liquid ethanol,C₂H₆O, is placed in a refrigerator and reaches equilibrium with its va
Mama L [17]

The mass of ethanol present in the vapor is 8.8×10⁻²g. when liquid and vapor ethanol at equilibrium.

The volume of the bottle = 4.7 L

Mass of ethanol = 0.33 g

Temperature (T1) = -11 oC = 273-11 = 262 K

P1 = 6.65 torr

Now we will calculate the mole by applying the ideal gas equation:-

PV = nRT

Or, n = PV/RT

Where P is the pressure

 T is the temperature

 R is the gas constant = 0.0821 L atm mol-1K-1

 V is the volume

Substituting the values of P, V, T, and R the mole of ethanol is calculated as:-

  = 0.001913 mol C2H6

Conversion of the mole to gm

Molar mass of ethanol (M) = 46.07 g/mol

Mass of C2H6O =0.001913 mol C2H6O 46.07 g/mol = 0.088 =  8.8×10⁻²g.

Hence, the mass of ethanol present in the vapor is found to be  8.8×10⁻²g.

Learn more about mole here:-brainly.com/question/15374113

#SPJ4

8 0
1 year ago
The part in the middle with a coil of wire wrapped around a metal shaft is part of an electric motor. What is it?
evablogger [386]

Answer:

  rotor

Explanation:

The part of the motor being pointed to is called the <em>rotor</em>.

4 0
3 years ago
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The energy of moving atoms is
balandron [24]

The answer is Thermal Energy :)

4 0
3 years ago
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When 0.491 grams of a protein were dissolved in 44 mL of benzene at 24.4 degrees C, the osmotic pressure was found to be 50.9 to
Ira Lisetskai [31]

Answer:

4057.85 g/mol

Explanation:

Hello, the numerical procedure is shown in the attached file.

- In this case, since we don't have the density of the protein, we must assume that the volume of the solution is solely given by the benzene's volume, in order to obtain the moles of the solute (protein).

-Van't Hoff factor is assumed to be one.

Best regards.

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3 years ago
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