Answer:
110,4 kJ / mole of acid
Explanation:
The reaction of NaOH with H₂SO₄ is:
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
Moles of NaOH and H₂SO₄ are:
0,1000L×1,00M = 0,100 moles of NaOH and 0,100 moles of H₂SO₄. As 2 moles of NaOH reacts with 1 mole of H₂SO₄, moles of acid that react are 0,100/2 = <em>0,0500moles of acid</em>.
The produced heat is:
Q = C×m×ΔT
Where C is specific heat capacity (4,18J/gK)
m is mass: 200,0mL×(1,00g/mL) = 200g
ΔT is change in temperature: 30,6°C - 24,0°C = 6,6°C = 6,6K
Thus, Q is:
Q = 4,18J/gK×200g×6,6K
Q = 5518J = <em>5,52kJ</em>
ΔH in kJ per mole of acid:
5,52kJ / 0,0500moles of acid =<em> 110,4 kJ / mole of acid</em>
<em />
I hope it helps!
