Please please please help me!
1 answer:
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We can use SOH, CAH and TOA, but first we must find the length of a hypotenuse:
h =
sin (theta)= 2/√13
cos ( theta) = -3/√13
tan (theta) = -2/3
cot (theta ) = -3/2
sec (theta) = 1/cos(theta ) = -√13/3
csc(theta ) = 1/ sin (theta) = √13/2
h =
sin (theta)= 2/√13
cos ( theta) = -3/√13
tan (theta) = -2/3
cot (theta ) = -3/2
sec (theta) = 1/cos(theta ) = -√13/3
csc(theta ) = 1/ sin (theta) = √13/2
1. Consider the tree diagram in the picture attached.
2 Each of the games picked can be a W (win) or a L (lose), the chances are equal
3. All that could happen in 4 picked games is shown in the picture:
2 w 2 l can happen in the following 6 ways: {(W,W,L,L)(W,L,W,L)(W,L,L,W)(L,W,W,L)(L,W,L,W)(L,L,W,W)}
4. P(2W,2L)=6/16=3/8
2 Each of the games picked can be a W (win) or a L (lose), the chances are equal
3. All that could happen in 4 picked games is shown in the picture:
2 w 2 l can happen in the following 6 ways: {(W,W,L,L)(W,L,W,L)(W,L,L,W)(L,W,W,L)(L,W,L,W)(L,L,W,W)}
4. P(2W,2L)=6/16=3/8