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Phoenix [80]
3 years ago
10

Is the sequence arithmetic? If so identify the common difference 15 22 35 46

Mathematics
2 answers:
Mrac [35]3 years ago
7 0
For a sequence to be arithmetic, the difference between each value must be the same.
15, 22, 35, 46
22 - 15 = 7
35 - 22 = 13
7 does not equal 13, so there is no common difference.
If there is no common difference, the sequence is not arithmetic.
olganol [36]3 years ago
4 0
15, 22, 35, 46

46 - 35 = 11
35 - 22 = 13
22 - 15 = 7

No, this sequence is not arithmetic, so it doesn't have a common difference.
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3 (5x + 7) = 75<br><br> what is x?
garik1379 [7]

Answer:

3 (5x+7) = 75

15x + 21 = 75

15x + 21 - 21 = 75 - 21

15x = 54

x = 3.6

Step-by-step explanation:

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Hey, I was just wondering what is 1/3 + 1/2?
cestrela7 [59]

Answer:

5/6

Step-by-step explanation:

1/3 x 2/2 = 2/6

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2/6 + 3/6 = 5/6

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Judy took $30 with her to spend on popcorn and drinks for herself and her friends at the movie theater. The price for each bag o
STatiana [176]

This is correct.


Hope it helps :)

6 0
3 years ago
Please help!! I have less than an hour to turn this in!
valentinak56 [21]

Answer:

8 × 10¹

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don't panic. just breathe deeply and then think logically.

0.002 ... what is that ? 2 10ths ? 2 hundredths ? 2 thousandths ? 2 tenthousandths ?

the 3rd position after the decimal point is for 1/1000.

and that means 10^-3. in the same way as 1000 is 10³.

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the other rounded number is then 4 × 10⁴.

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we combine the same types of factors, like the basic constants : 2×4 = 8

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what hairball when we multiply the same base number with exponents ? we add the exponents :

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7 0
2 years ago
How many different 10 person committees can be selected from a pool of 23 people?
Salsk061 [2.6K]

We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.

We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.

Formula for combination:

C(n,r)=\dfrac{n!}{(n-r)!r!}

Where n represents the number of objects/people in the set and r represents the number of objects/people being chosen from the set

There are 23 people in the set and 10 people being chosen from the set

C(23,10)=\dfrac{23!}{(23-10)!10!}

=\dfrac{23!}{13!\times10!}

Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

=1,144,066

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
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