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Ket [755]
3 years ago
10

Which climate conditions are typical of regions near the North Pole and the South Pole

Chemistry
1 answer:
denis23 [38]3 years ago
6 0
<span>The main feature of the climate is that there are not such things as warm summers there and that the temperature almost never exceeding 10-20 degrees celsius in the summer. In the winter it goes as much as -50 celsius. There are no trees while the land comprises glaciers and tundras. The two climates are the coldest places on earth. </span>
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Which type of galaxy forms when two other galaxies crash into each other? They are small galaxies made up of bright, young stars
GenaCL600 [577]

Answer:

elliptical galaxy

Explanation

:The combination of the two galaxies then forms what appears to be an elliptical galaxy as the arms begin to disappear. The merger of gasses creates new stars, and the new shape becomes more elliptical, globular, or sometimes irregular.

4 0
2 years ago
Liquid hexane
maks197457 [2]

<u>Answer:</u> The mass of H_2O produced is 2.52 g

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

  • <u>For hexane:</u>

Given mass of hexane = 1.72 g

Molar mass of hexane = 86.18 g/mol

Putting values in equation 1, we get:

\text{Moles of hexane}=\frac{1.72g}{86.18g/mol}=0.020mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 8.0 g

Molar mass of oxygen gas= 32 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{8.0g}{32g/mol}=0.25mol

The chemical equation for the combustion of hexane follows:

2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O

By stoichiometry of the reaction:

If 2 moles of hexane reacts with 19 moles of oxygen gas

So, 0.020 moles of hexane will react with = \frac{19}{2}\times 0.020=0.19mol of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, hexane is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of hexane produces 14 moles of H_2O

So, 0.020 moles of hexane will produce = \frac{14}{2}\times 0.020=0.14mol of H_2O

We know, molar mass of H_2O = 18 g/mol

Putting values in above equation, we get:

\text{Mass of }H_2O=(0.14mol\times 18g/mol)=2.52g

Hence, the mass of H_2O produced is 2.52 g

4 0
3 years ago
N methyl 2 pyrrolidone heated with aqueous acid reaction
monitta
<span>N-methyl 2 pyrrolidone is a cyclic amide and it when heated with aqueous acid gives the product as a cyclic amino acid. The product name is </span><span>N-Methyl-4-aminobutyric acid</span><span>

The reaction is given as follows in the attached picture.

</span>

5 0
3 years ago
Which element will have a greater chance of a momentary dipole neon or krypton?
djverab [1.8K]
_Brainliest if helped!

Neon, as it is of smaller size.  U can take the dipole strength as proportional to Charge/Radius  , they have "same charge" but different radius.
7 0
3 years ago
Complete combustion of 8.60 g of a hydrocarbon produced 26.5 g of CO2 and 12.2 g of H2O. What is the empirical formula for the h
amid [387]

The empirical formula of the hydrocarbon is C_2H_3 if combustion of 8.60 g of a hydrocarbon produced 26.5 g of CO_2 and 12.2 g of H_2O.

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule CH_2O is the empirical formula for glucose.

1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon.

Hence, in this case the mass of carbon in 8.46 g of CO_2:

(\frac{12}{44}) × 8.46 = 2.3073 g

1 mole of water contains 18 g, out of which 2 g is hydrogen;

Therefore, 2.6 g of water contains;

(\frac{2}{18} × 2.6 = 0.2889 g of hydrogen.

Therefore, with the amount of carbon and hydrogen from the hydrocarbon, we can calculate the empirical formula.

We first calculate the number of moles of each,

Carbon = \frac{2.3073}{12}  = 0.1923 moles

Hydrogen = \frac{0.2889}{1}= 0.2889 moles

Then, we calculate the ratio of Carbon to hydrogen by dividing by the smallest number value;

            Carbon : Hydrogen

               \frac{0.1923}{0.1923} : \frac{0.2889}{0.1923}

                      1 :  1.5

                     (1 : 1.5) 2

                    = 2 : 3

Hence, the empirical formula of the hydrocarbon is C_2H_3.

Learn  more about the empirical formula here:

brainly.com/question/14044066

#SPJ1

8 0
2 years ago
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