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3 years ago

Which climate conditions are typical of regions near the North Pole and the South Pole

1 answer:

6 0

<span>The main feature of the climate is that there are not such things as warm summers there and that the temperature almost never exceeding 10-20 degrees celsius in the summer. In the winter it goes as much as -50 celsius. There are no trees while the land comprises glaciers and tundras. The two climates are the coldest places on earth. </span>

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What is inertia?

Savatey [412]

Answer:

Explanation:

The answer would be A because Inertia is when a property of matter remains unchanged.

4 0

3 years ago

Read 2 more answers

Aspartame is a sweetner that is 160 times sweeter than sucrose (table sugar) when dissolved in water. The molecular formula of a

NikAS [45]

Answer:

<u><em>294.307 g/mol</em></u>

Explanation:

The first question for this statment is:

<em>Calculate the gram-formula-mass of aspartame. </em>

<em />

<h2>Solution</h2>

The chemical formula is:

$C_{14}H_{18}N_2O_5 .$

The <em>gram-formula-mass </em>is calculated adding the masses for all the atoms in the molecular formula:

Atom Number of atoms Atomic mass Total mass

g/mol g/mol

C 14 12.011 14 × 12.011 = 164.154

H 18 1.008 18 × 1.008 = 18.144

N 2 14.007 2 × 14.007 = 28.014

O 5 15.999 5 × 15.999 = 79.995

===================

Total 294.307 g/mol

Answer: 294.307 g/mol

6 0

3 years ago

Murcury is the only metal at room temperature. Its density is 13.6g/mL. How many grams of murcury will occupy a volume of 95.8mL

Hatshy [7]

Answer:

<h3>The answer is 1.30288 × 10³ g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 95.8mL

density = 13.6g/mL

We have

mass = 13.6 × 95.8 = 1302.88

We have the final answer as

Hope this helps you

3 0

3 years ago

. How many grams of water would require 4400 joules

Alja [10]

Answer:

The specific heat of water is 4.18 J/g C.

Explanation:

Never forget that!

2200

⋅

4.18

⋅

∴

≈

8.0

5 0

3 years ago

Concerning Boyle's Law, if you had a gas at a pressure of 101 kPa and decreased the volume of the container holding the gas to o

Viefleur [7K]

Answer:

$P_2=404 kPa$

Explanation:

Hello,

In this case, the Boyle's is mathematically defined via:

$P_1V_1=P_2V_2$

Which stands for an inversely proportional relationship between volume and pressure, it means the higher the volume the lower the pressure and vice versa. In such a way, since the volume is decreased to one quarter, we can write:

$V_2=\frac{1}{4} V_1$

We can compute the new pressure:

$P_2=\frac{P_1V_1}{V_2} =\frac{P_1V_1}{\frac{1}{4} V_1} =\frac{101kPa*V_1}{\frac{1}{4} V_1} \\\\P_2=4*101kPa\\\\\\P_2=404 kPa$

Which means the pressure is increased by a factor of four.

Regards.

7 0

3 years ago