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postnew [5]
3 years ago
13

What mass of Al would be obtained from the complete reduction of 10.2 tonnes of Al2O3?

Chemistry
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

5.4 tonnes.

Explanation:

The first step is to find the molar mass of Al2O3. Aluminum has a molar mass of about 27 and oxygen has a molar mass of about 16, so 2(27)+3(16)= 102g/mol=0.102kg/mol. 10200kg/0.102kg/mol=100,000 moles of Al2O3 in 10.2 tonnes. Multiplying this by the molar mass of the two aluminums, you get a total of 54*100,000=5400000g=5400kg=5.4 tonnes. Hope this helps!

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Explanation:

6 0
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Is Naci a metal or none metel
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3 years ago
How many moles of KBr will be produced from 10.51 moles of BaBr2?
gregori [183]

Answer:

21.02moles of KBr

Explanation:

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Complete reaction equation:

           BaBr₂ + K₂SO₄ → KBr + BaSO₄

Upon inspecting the given equation, we find out that the atoms are not balanced on both sides of the equation:

        The balanced equation is:

           BaBr₂ + K₂SO₄ → 2KBr + BaSO₄

From the equation:

     1 mole of BaBr₂ produces 2 moles of KBr

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7 0
3 years ago
What volume would a 0. 250 mole sample of h2 gas occupy if it had a which a a pressure of 1. 70 atm and a temperature of 35 C?
frosja888 [35]

The volume of  0. 250 mole sample of H_{2} gas occupy if it had a pressure of 1. 70 atm and a temperature of 35 °C is  3.71 L.

Calculation,

According to ideal gas equation which is known as ideal gas law,

PV =n RT

  • P is the pressure of the hydrogen gas  = 1.7 atm
  • Vis the volume of the hydrogen gas = ?
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By putting all the values of the given data like pressure temperature universal gas constant and number of moles in equation (i) we get ,

1.7 atm×V = 0.25 mole ×0.082 × 208 K

V = 0.25 mole ×0.082atm L /mole K × 308 K /1.7 atm

V = 3.71 L

So, volume of the sample of the hydrogen gas occupy is  3.71 L.

learn more about ideal gas equation

brainly.com/question/4147359

#SPJ4

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1 year ago
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