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skad [1K]
2 years ago
12

Which ion does not have a noble gas configuration in its ground state? which ion does not have a noble gas configuration in its

ground state? al3+ sc3+ as3- ga3+?
Chemistry
2 answers:
loris [4]2 years ago
7 0

The correct answer is Ga3+.  

Electron configuration of Al is [Ne] 3s2 3p1  

Electron configuration of Al3+ is [Ne]  

So the electron configuration of Al3+ is like that of Ne.  


Electron configuration of Sc is [Ar] 3d1 4s2  

Electron configuration of Sc3+ is [Ar]  

So the electron configuration of Sc3+ is like that of Ar.  


Electron configuration of As is [Ar] 3d10 4s2 4p3  

Electron configuration of As3- is [Ar] 3d10 4s2 4p6

So the electron configuration of As3- is like that of Kr

Electron configuration of Kr [Ar] 3d10 4s2 4p6  


Electron configuration of Ga is [Ar] 3d10 4s2 4p1

Electron configuration of Ga3+ is [Ar]3d10

The presence of the ten d orbital electrons prevents Ga3+ from having the same electron configuration as Argon.  

All other choices have the same electron configurations as a noble gas.  


Luda [366]2 years ago
4 0

Answer: Option (d) is the correct answer.

Explanation:

The atomic number of Al is 13, so the electronic configuration of Al is as follows.

            1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}

         = [Ne]3s^{2}3p^{1}

Al^{3+} = [Ne]

The atomic number of Sc is 21, so the electronic configuration of Sc is as follows.

         1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{1}

        = [Ar]4s^{2}3d^{1}

 Sc^{3+} = [Ar]

The atomic number of As is 33, so the electronic configuration of As is as follows.

         1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{3}

         = [Ar]4s^{2}3d^{10}4p^{3}

 As^{3-} = [Ar]4s^{2}3d^{10}4p^{6} = [Kr]

The atomic number of Ga is 31, so the electronic configuration of Ga is as follows.

        1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{1}

       = [Ar]4s^{2}3d^{10}4p^{1}

 Ga^{3+} = [Ar]3d^{10}

Therefore, we can conclude that galium (Ga) ion does not have a noble gas configuration in its ground state.

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3 years ago
-. Convert 54 m to its equivalent measurement in cm.
Sergio [31]

Answer:

5400 cm

Explanation:

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What is the law of conservation?
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3 years ago
Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --> NaKP(aq)+H2O(I)
Natali [406]

Answer:

<u />

  • <u>a) 1.44g</u>

<u />

  • <u>b) 77.3%</u>

<u />

Explanation:

<u>1. Chemical balanced equation (given)</u>

       NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)

<u>2. Mole ratio</u>

1molNaOH(aq):1molKHP(s)

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

<u />

<u>3. Find the number of moles in 72.14 mL of the base</u>

    Molarity=\text{number of moles of solute}/\text{volume of solution in liters}

    \text{Volume of solution}=72.14mL=0.07214liters

     \text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol

<u>4. Find the number of grams of KHP that reacted</u>

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

  • mass = number moles × molar mass = 0.007055mol × 204.23g/mol
  • mass = 1.4408 g.

You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

<u>5. Find the percentage of KHP in the sample</u>

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

  • % = (mass of substance / mass of sample) × 100

  • % = (1.4408g/ 1.864g) × 100 = 77.3%
7 0
2 years ago
How many grams are in 3.14 moles of PI₃?
OverLord2011 [107]

Answer:

\boxed {\boxed {\sf 1290 \ g \ PI_3}}

Explanation:

We want to convert from moles to grams, so we must use the molar mass.

<h3>1. Molar Mass</h3>

The molar mass is the mass of 1 mole of a substance. It is the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We are given the compound PI₃ or phosphorus triiodide. Look up the molar masses of the individual elements.

  • Phosphorus (P): 30.973762 g/mol
  • Iodine (I): 126.9045 g/mol

Note that there is a subscript of 3 after the I in the formula. This means there are 3 moles of iodine in 1 mole of the compound PI₃. We should multiply iodine's molar mass by 3, then add phosphorus's molar mass.

  • I₃: 126.9045 * 3=380.7135 g/mol
  • PI₃: 30.973762 + 380.7135 = 411.687262 g/mol

<h3>2. Convert Moles to Grams</h3>

Use the molar mass as a ratio.

\frac {411.687262 \ g \ PI_3}{ 1 \  mol \ PI_3}

We want to convert 3.14 moles to grams, so we multiply by that value.

3.14 \ mol \ PI_3 *\frac {411.687262 \ g \ PI_3}{ 1 \  mol \ PI_3}

The units of moles of PI₃ cancel.

3.14 *\frac {411.687262 \ g \ PI_3}{ 1 }

1292.698 \ g\ PI_3

<h3>3. Round</h3>

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the tens place.

  • 1292.698

The 2 in the ones place tells us to leave the 9.

1290 \ g \ PI_3

3.14 moles of phosphorous triiodide is approximately equal to <u>1290 grams of phosphorus triodide.</u>

4 0
2 years ago
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