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ANTONII [103]
3 years ago
15

Mars has a mass of about 6.4 x 1023 kg, and its moon Phobos has a mass of about 9.6 x 1015 kg. If the magnitude of the gravitati

onal force between the two bodies is 4.6 x1015 N, how far apart are Mars and Phobos?
Physics
1 answer:
Sliva [168]3 years ago
8 0

Answer:9.55×10^-4 metre

Explanation:

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The rate at which work is done is power

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What happens when the data in an investigation does not support the origanal hypothesis
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Explanation:

The data is altered so that it supports the original hypothesized. The data is then altered so that it supports the original hypothesis.

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Which is a property of ionic compounds?
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Able to conduct electricity
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Light propagate faster through medium “a” than medium “b”
dangina [55]

1) Medium "b" has more optical density

2) Light must hit the interface between the two mediums perpendicularly

Explanation:

1)

Refraction occurs when light propagates from a medium into a second medium.

The optical density of a medium is given by its index of refraction, which is defined as:

n=\frac{c}{v}

where

c is the speed of light in a vacuum

v is the speed of light in a medium

Higher index of refraction means higher optical density, and light propagater slower into a medium with higher optical density.

In this problem, light propagates faster through medium "a" than medium "b": this means that medium "a" has lower refractive index of medium "b", and so "b" has more optical density.

2)

We can answer this part by referring to Snell's law, which gives the relationship between the direction of the incident ray and of the refracted ray when light passes through the interface between two media:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n_1, n_2 are the index of refraction of the two mediums

\theta_1, \theta_2 are the angle of incidence and of refraction (the angle that light makes with the normal to the surface in medium 1 and medium 2)

Here we want the direction of propagation of the light ray not to change: this means that it must be

sin \theta_1 = sin \theta_2 (1)

However, here we have two mediums "a" and "b" with different index of refraction, so

n_1\neq n_2

Therefore the only angle that can satisfy eq.(1) is

\theta_1 = \theta_2 = 0

So, the light must hit the surface perpendicular to the interface between the two mediums.

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

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3 years ago
I need help for a assignment NOT A QUIZ
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Answer:

what

ITS BLANK FOR ME I WISH I COULD HELP YOU

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