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Nina [5.8K]
4 years ago
14

An antigen is a protein made by your body to respond to a specific foreign molecule.

Physics
1 answer:
Tom [10]4 years ago
8 0

hope this helps it's F

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If a wave has amplitude of 0.2 meters, a wavelength of 0.5 meters, and a frequency of 32 Hz, at what speed is it moving?
GarryVolchara [31]
The velocity, frequency and wavelength of a wave are related by:
v = fλ
v = 32 x 0.5
v = 16 m/s
The answer is B.
3 0
3 years ago
A car is traveling at 108 km/h, stuck behind a slower car. Finally the road is clear and the car pulls over to make a pass. The
mezya [45]

Answer:

The average acceleration of the car is 2.143 meters per square second.

Explanation:

Let assume that car accelerates uniformly, in that case, we can obtain the value of acceleration by using the following equation of motion:

v = v_{o}+a\cdot t

Where:

v_{o} - Initial velocity, measured in meters per second.

v - Final velocity, measured in meters per second.

a - Acceleration, measured in meters per square second.

t - Time, measured in seconds.

Now, we clear acceleration within expression:

a = \frac{v-v_{o}}{t}

Initial and final velocities are now converted from kilometers per hour into meters per second:

v_{o} = \left(108\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

v_{o} = 30\,\frac{m}{s}

v = \left(135\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

v = 37.5\,\frac{m}{s}

If we know that t = 3.5\,s, then, the average acceleration of the car is:

a = \frac{37.5\,\frac{m}{s}-30\,\frac{m}{s} }{3.5\,s}

a = 2.143\,\frac{m}{s^{2}}

The average acceleration of the car is 2.143 meters per square second.

8 0
3 years ago
Find the magnitude of the average induced emf in the coil when the magnet is turned off and the field decreases to 0 T in 2.8 s
Ostrovityanka [42]

Answer:

<em>2.15 mV</em>

<em></em>

Explanation:

The complete question is

You have a coil of wire with 17 turns each of 1.5 cm radius. You place the plane of the coil perpendicular to a 0.50-TB?  field produced by the poles of an electromagnet.

Find the magnitude of the average induced emf in the coil when the magnet is turned off and the field decreases to 0 T in 1.9 s .

Radius of the coil = 1.5 cm = 0.015 m

number of turns = 17

Initial magnetic field B_{1} = 0.50 T

Final magnetic field B_{2} = 0 T

time taken dt = 1.9 s

Area pf the coil = πr^{2} = 3.142 x 0.015^{2} = 7.1 x 10^-4 m^2

magnetic flux = BA

initial flux = B_{1}A = 0.5 x 7.1 x 10^-4 = 3.55 x 10^-4 Wb

Final flux = B_{2}A = 0 x 7.1 x 10^-4 = 0 Wb

change in flux dФ = 3.55 x 10^-4  -  0 = 3.55 x 10^-4 Wb

Induced EMF E = NdФ/dt = (17 x 3.55 x 10^-4)/2.8 = 2.15 x 10^-3 V

==> <em>2.15 mV</em>

7 0
4 years ago
Question 3 of 5 What happens to the particles in a substance as it melts? O A. The particles slow down and become fixed in place
Mars2501 [29]

Answer:

D. The particles move more quickly and begin to move from place to place.

Explanation:

4 0
3 years ago
A 47.0 kg uniform rod 4.25 m long is attached to a wall with a hinge at one end. The rod is held in a horizontal position by a w
Crank

Answer:

2.79 m

Explanation:

Use the static equilibrium condition, net torque actin on the system is zero.

\sum \tau= 0

T(Lsin\theta)- Mg\frac{L}{2}-mgx=0

solve for the distance of the person from the wall x

x= \frac{TLsin\theta-Mg(L/2)}{Mg}

now putting the values we get

x= \frac{1350\times4.25sin30-47\times9.81\times(4.25/2)}{69\times9.80}

= 2.79 m

4 0
3 years ago
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