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murzikaleks [220]
3 years ago
13

A spherical balloon is partially blown up and its surface area is measured. More air is then added, increasing the volume of the

balloon. If the surface area of the balloon expands by a factor of 2.00 during this procedure, by what factor does the radius of the balloon increase? The radius of the balloon increases by a factor of _________.
Physics
1 answer:
Aloiza [94]3 years ago
5 0

Answer:

√2 or 1.414

Explanation:

Area of a sphere

A=4\pi r^2

Initial area of the balloon

A_1=4\pi r_1^2

Final area of the balloon

A_2=4\pi r_2^2

Given that

A_2=2\times A_1\\\Rightarrow 4\pi r_2^2=2\times 4\pi r_1^2\\\Rightarrow r_2^2=2r_1^2\\\Rightarrow r_2=\sqrt{2}r_1=1.414r_1

Hence, the radius increases by a factor of √2 or 1.414

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Projectiles that strike objects are good examples of inelastic collisions. A 0.1 kg nail driven by a gas powered nail driver col
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In an inelastic collision, only momentum is conserved, while energy is not conserved.

1) Velocity of the nail and the block after the collision
This can be found by using the total momentum after the collisions:
p_f=(m+M)v_f=4.8 kg m/s
where
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3 years ago
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Find the equivalent resistance, current, and voltage across each resistor when the specified resistors are connected across a 20
timama [110]

Answer:

Explanation:

The question is incomplete. Here is the complete question.

"Find the equivalent resistance, the current supplied by the battery and the current through each resistor when the specified resistors are connected across a 20-V battery. Part (a) uses two resistors with resistance values that can be set with the animation sliders, and you can use the animation to verify your calculation. In part (b), three resistors are specified. (a) Two resistors are connected in series across a 20-V battery. Let R1 = 1 Ω and R2 = 2 Ω. Rea = (b) Add a third resistor to the circuit in series. Let R1 = 1 Ω, R2 = 2 Ω, and R3 = 3 Ω"

Using ohms law formula to solve the problem

E = IRt

E is the supply voltage

I is the total current

Rt is the total equivalent resistant.

a) Given two resistances

R1 = 1ohms and R2 = 2ohms

If the resistors are Connected in series across a 20V supply voltage,

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= 1ohms + 2ohms

= 3ohms

- In a series connected circuit, same current flows through the resistors.

Using the formula E = IRt

I = E/Rt

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I = 6.67A

The current in both resistors is 6.67A

- Different voltage flows across a series connected circuit.

Using the formula V = IR

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For 1ohms resistor,

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b) If the resistors are three

R1 = 1ohms, R2 = 2ohms R3 = 3ohms

- Total equivalent resistance = 1+2+3

= 6ohms

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I = 20/6

I = 3.33A

Since the same current flows through the resistors, the current across each of them is 3.33A

- Voltage across them is calculated as shown:

V = IR

For 1ohm resistor

V = 3.33×1

V = 3.33volts

For 2ohms resistor

V = 3.33×2

V = 6.66volts

For 3ohms resistor

V = 3.33×3

V = 9.99volts

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