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murzikaleks [220]
2 years ago
13

A spherical balloon is partially blown up and its surface area is measured. More air is then added, increasing the volume of the

balloon. If the surface area of the balloon expands by a factor of 2.00 during this procedure, by what factor does the radius of the balloon increase? The radius of the balloon increases by a factor of _________.
Physics
1 answer:
Aloiza [94]2 years ago
5 0

Answer:

√2 or 1.414

Explanation:

Area of a sphere

A=4\pi r^2

Initial area of the balloon

A_1=4\pi r_1^2

Final area of the balloon

A_2=4\pi r_2^2

Given that

A_2=2\times A_1\\\Rightarrow 4\pi r_2^2=2\times 4\pi r_1^2\\\Rightarrow r_2^2=2r_1^2\\\Rightarrow r_2=\sqrt{2}r_1=1.414r_1

Hence, the radius increases by a factor of √2 or 1.414

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Answer:

The work done by the bird is 0.762 J

Explanation:

Given;

force applied by the bird, f = 10 N

distance the bird moved the worm, d = 3 inches = 0.0762 m

The work done by the bird is given by;

W = F x d

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A force, F1, of magnitude 2.0 N and directed due east is exerted on an object. A second force exerted on the object is F2 = 2.0
IgorLugansk [536]

Answer:

Magnitude of the force is

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Explanation:

As we know that force is a vector quantity and in order to find the resultant of two or more forces we need to add them vectorialy

So here we have

\vec F_1 + \vec F_2 + \vec F_3 = 0

here we know that first force is of magnitude 2 N towards east

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2\hat i + 2\hat j + \vec F_3 = 0

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3 0
2 years ago
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Answer:

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Therefore,

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