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Ghella [55]
3 years ago
5

ou have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 10-5 T). If

your solenoid has 450 turns and is 29 cm long, determine the current you must use in order to obtain a magnetic field of the desired magnitude.
Physics
1 answer:
Nikitich [7]3 years ago
5 0

Answer:

I = 0.0256 A

Explanation:

Given,

Magnetic field, B = 5 x 10⁻⁵ T

Number of turns, N = 450

length = 29 cm

Current,I = ?

Using formula of magnetic field due to solenoid

B = \mu_0 NI

I = \dfrac{B}{\mu_0N}

I = \dfrac{5\times 10^{-5}\times 0.29}{450\times 4\pi \times 10^{-7}}

I = 0.0256 A

Hence, the current obtained is equal to 0.0256 A.

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a van moves with a constant speed of 79 km/h how long will it take to travel a distance of 502 kilometers
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Answer:

6.35hours

Explanation:

s=vt

t=s/v=502/79=6.35hours

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A softball has a mass of 0.18 kg. What is the gravitational force on Earth due to the ball, and what is the Earth's resulting ac
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Answer:F=1.7802

Explanation:

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F=.18×9.89

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A disk shaped grindstone of mass 3.0 kg and radius 8 cm is spinning at 600 rpm. After the power is shut off the frictional torqu
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Answer:

\theta=50\ revolution

Explanation:

It is given that,

Mass of the grindstone, m = 3 kg

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Initial speed of the grindstone, \omega_i=600\ rpm=62.83\ rad/s

Finally it shuts off, \omega_f=0

Time taken, t = 10 s

Let \alpha is the angular acceleration of the grindstone. Using the formula of rotational kinematics as :

\alpha =\dfrac{\omega_f-\omega_i}{t}

\alpha =\dfrac{0-62.83}{10}

\alpha =-6.283\ rad/s^2

Let \theta is the number of revolutions of the grindstone after the power is shut off. Now using the third equation of rotational kinematics as :

\omega_f^2-\omega_i^2=2\alpha \theta

\theta=\dfrac{\omega_f^2-\omega_i^2}{2\alpha }

\theta=\dfrac{-62.83^2}{2\times -6.283}

\theta=314.15\ radian

\theta=49.99\ revolution

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7 0
3 years ago
We know that the motion of the Moon around the Earth is due
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Answer:

YES

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A stream moving with a speed of 7.1 m/s reaches a point where the cross-sectional area of the stream decreases to one half of th
lana66690 [7]

Answer:

14.2 m/s

Explanation:

Given data:

Speed of the stream, v₁ = 7.1 m/s

let the cross section area at initial point be A₁

now area at the second point, A₂ = (1/2)A₁ = 0.5A₁

now, from the continuity equation, we have

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or

v₂ = 14.2 m/s

8 0
3 years ago
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