Question

ou have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 10-5 T). If your solenoid has 450 turns and is 29 cm long, determine the current you must use in order to obtain a magnetic field of the desired magnitude.

Answer 1

Answer:

$I = 0.0256 A$

Explanation:

Given,

Magnetic field, B = 5 x 10⁻⁵ T

Number of turns, N = 450

length = 29 cm

Current,I = ?

Using formula of magnetic field due to solenoid

$B = \mu_0 NI$

$I = \dfrac{B}{\mu_0N}$

$I = \dfrac{5\times 10^{-5}\times 0.29}{450\times 4\pi \times 10^{-7}}$

$I = 0.0256 A$

Hence, the current obtained is equal to 0.0256 A.