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3 years ago

14

Really struggling! Will give 20 points to answers correctly

2 answers:

Rom4ik [11]3 years ago

8 0

Answer:

8,820

Step-by-step explanation:

One candle:

½ × 10 × 7 × 6

= 210 cm³

42 candles:

42 × 210

= 8,820 cm³

Stolb23 [73]3 years ago

8 0

Answer:

8820 cm^3

Step-by-step explanation:

Volume of one prism = A(base prism)*height(prism)

A(base prism)= A(triangle) = 1/2*(base triangle)*Height(triangle)= 1/2*10*7 = 35 cm^2

Volume of one prism(or one candle) = A(base prism)*height(prism)= 35*6=210 cm^3

Volume of 42 candles = 210*42= 8820 cm^3

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Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

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Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

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$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

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Case 2: If r is negative, then using (ii) we get

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$\dfrac{6}{0.5}=a$

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The sum of first 6 terms is

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$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

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