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dalvyx [7]
3 years ago
14

QUESTION 2. the feasible region shows the number of chairs x and tables y that a furniture company can build each week.

Mathematics
1 answer:
GalinKa [24]3 years ago
3 0

Answer:

Part a) The company can not build 12 chairs and 5 tables

Part b) The company can build 18 chairs and 3 tables

Part c) The company  can build 12,13,14,15,16 or 17 chairs

Step-by-step explanation:

we know that

If a ordered pair is a solution, then the ordered pair must be belong to the feasible region of the graph

Part a) Can the company build 12 chairs and 5 tables?

In this problem we have the ordered pair A(12,5)

Plot  and verify if the point belong to the feasible region of the graph

see the attached figure to better understand the problem

The point A is not on the feasible region

therefore

The company can not build 12 chairs and 5 tables

Part b) Can the company build 18 chairs and 3 tables?

In this problem we have the ordered pair B(18,3)

Plot  and verify if the point belong to the feasible region of the graph

see the attached figure to better understand the problem

The point B is on the feasible region

therefore

The company can build 18 chairs and 3 tables

Part c) One week, the company decides to build 4 tables. how many chairs can the company build?

For y=4

Find the value of x in the graph

The solutions point for y=4 tables are

(12,4), (13,4),(14,4),(15,4),(16,4) and (17,4)

therefore

The company  can build 12,13,14,15,16 or 17 chairs

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Step-by-step explanation:

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As we can  see from the figure that ∠JOP and ∠JKP are on the same segment JP. Hence, ∠JOP and ∠JKP are congruent and the angle of ∠JKP is 84°

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Juli2301 [7.4K]

Answer:

<h3>\boxed{ \frac{24}{5} }</h3>

Step-by-step explanation:

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Convert mixed number to improper fraction

\mathrm{3( \frac{5}{2}  - 1) +  \frac{3}{10} }

Calculate the difference

⇒\mathrm{3( \frac{5 \times 1}{2 \times 1} -  \frac{1 \times 2}{1 \times 2}  }) +  \frac{3}{10}

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Calculate the product

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⇒\mathrm{ \frac{45 + 3}{10 } }

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Reduce the numerator and denominator by 2

⇒\mathrm{ \frac{24}{5} }

Further more explanation:

<u>Addition </u><u>and </u><u>Subtraction</u><u> </u><u>of </u><u>like </u><u>fractions</u>

While performing the addition and subtraction of like fractions, you just have to add or subtract the numerator respectively in which the denominator is retained same.

For example :

Add : \mathsf{ \frac{1}{5}  +  \frac{3}{5}  =  \frac{1 + 3}{5} } =  \frac{4}{5}

Subtract : \mathsf{ \frac{5}{7}  -  \frac{4}{7}  =  \frac{5 - 4}{7}  =  \frac{3}{7} }

So, sum of like fractions : \mathsf{ =  \frac{sum \: of \: their \: number}{common \: denominator} }

Difference of like fractions : \mathsf{ \frac{difference \: of \: their \: numerator}{common \: denominator} }

<u>Addition </u><u>and </u><u>subtraction</u><u> </u><u>of </u><u>unlike </u><u>fractions</u>

While performing the addition and subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fractions. Thus, obtained fractions should be reduced into lowest terms if there are any common on numerator and denominator.

For example:

\mathsf{add \:  \frac{1}{2}  \: and \:  \frac{1}{3} }

L.C.M of 2 and 3 = 6

So, ⇒\mathsf{ \frac{1 \times 3}{2 \times 3}  +  \frac{1 \times 2}{3 \times 2} }

⇒\mathsf{ \frac{3}{6}  +  \frac{2}{6} }

⇒\frac{5}{6}

Multiplication of fractions

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.

When any number or fraction is divided by a fraction, we multiply the dividend by reciprocal of the divisor. Let's consider a multiplication of a whole number by a fraction:

\mathsf{4 \times  \frac{3}{2}  =  \frac{4 \times 3}{2}  =  \frac{12}{2}  = 6}

Multiplication for \mathsf{ \frac{6}{5}  \: and \:  \frac{25}{3} } is done by the similar process

\mathsf{ =  \frac{6}{5}  \times  \frac{25}{3}  = 2 \times 5 \times 10}

Hope I helped!

Best regards!

5 0
3 years ago
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