Answer:
in steps
Step-by-step explanation:
The question did not state if alpha>beta or alpha<beta, so the answer will have 2 answers for each questions
3x²-9x+2=0
x = (-(-9) ± √(-9)²-4*(3)*(2)) / (2*3)
x = (9 + √57) / 6 or x = (9 - √57) / 6 (alpha and beta) or (beta and alpha)
(I) alpha (a) ×beta (b) + alpha² × beta = ab (1+a)
= ((9 + √57) / 6) ((9 - √57) / 6) (1 + (9 ± √57))
= ((9² - (√57)²)/36) (10 ± √57)
= (24/36) (10 ± √57)
= 2/3 (10 ± √57) or (11.7 or 1.63)
(ii) alpha²-alpha×beta+beta² = a² -2ab + b² +ab = (a - b)² + ab
if a is alpha
= ((9 + √57) / 6) - ((9 - √57) / 6)) + ((9 + √57) / 6) ((9 - √57) / 6))
= √57/3 + 2/3
= (√57 + 2) / 3
if a is beta
((9 - √57) / 6) - ((9 + √57) / 6)) + ((9 - √57) / 6) ((9 + √57) / 6))
= - √57/3 + 2/3
= - (√57 + 2) / 3
Answer:
-13
Step-by-step explanation:
2x²+26x+156=0
x²+13x+78=0
x²+13x=-78
x²+13x+169/4=-143/4
(x+13/2)²=-143/4
x+13/2=(i√143)/2 or x+13/2=-(i√143)/2
x=(i√143)/2-13/2 or x=-(i√143)/2-13/2
(i√143)/2-13/2+(-(i√143)/2)-13/2=(i√143-13-i√143-13)/2=-26/2=-13
Answer:
15
Step-by-step explanation:
If you try to find how many times 3 goes into 45, it would be 15. Same thing with 6 and 90 and 8 and 120, they would all be 15.
68-33 blockers ?????????????????????????????????????????!?!!
A square with a side length of 4 would have an area of 16 because 4x4 equals 16.
