Answer:
electrons
Explanation:
The total charge Q is the sum of the charge of the N electrons contained in the sphere:

charge of a electron
We solve to find N:

Answer:
The peak emf of the generator is 40.94 V.
Explanation:
Given that,
Number of turns in primary coil= 11
Number of turns in secondary coil= 18
Peak voltage = 67 V
We nee to calculate the peak emf
Using relation of number of turns and emf


Where, N₁ = Number of turns in primary coil
N₂ = Number of turns in secondary coil
E₂ = emf across secondary coil
Put the value into the formula


Hence, The peak emf of the generator is 40.94 V.
Answer:
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Explanation:
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The magnitude of charge on a proton and electron is the same, 1.602 x 10-19 C. Protons are +, and electrons -.