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3 years ago

In the virtual lab, calculations were made of the predicted diffraction angle, using the formula

Physics

1 answer:

djyliett [7]3 years ago

6 0

Answer:

1. The predicted angle of diffraction with a 3 cm wavelength was degrees.

the answer is 57.3

2. The predicted angle of diffraction with a 4 cm wavelength was degrees.

the answer is 76.4

3. The predicted angle of diffraction with a 5 cm wavelength was degrees.

the answer is 95.5

Explanation:

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const2013 [10]

Answer:

The acceleration would be 3.455.

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3 years ago

You throw a glob of putty straight up toward the ceiling, which is 3.50 mm above the point where the putty leaves your hand. The

LuckyWell [14K]

Answer: $4.65\ m/s$

Explanation:

Given

Distance putty has to travel is 3.5 m

The initial speed of putty is 9.50 m/s

Using equation of motion to determine the velocity of putty just before it hits ceiling

$v^2-u^2=2as$

$\Rightarrow v^2-(9.5)^2=2(-9.8)(3.5)\\\\\Rightarrow v^2=9.5^2-68.6\\\Rightarrow v=\sqrt{90.25-68.6}\\\Rightarrow v=4.65\ m/s$

So, the velocity of putty just before hitting is $4.65\ m/s$

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3 years ago

What must the diver's minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, wh

Dafna1 [17]

Answer:

1.08 m/s

Explanation:

This can be solved with two steps, first we need to find the time taken to fall 9.5 m, then we can divide the horizontal distance covered with time taken to calculate the velocity.

Time taken to fall 9.5 m

vertical acceleration = a = 9.8 m/s^2.

vertical velocity = 0, (since there is only horizontal component for velocity, )

distance traveled s = 9.5 m.

Substituting these values in the equation

$s= u \timest+0.5at^{2}$

$t= \sqrt{\frac{2s}{g} }$

$t=\sqrt{\frac{2\times9.5}{9.8} }$

⇒ t= 1.392 sec

Velocity needed

We know the time taken (1.392 s) to travel 1.5 m,

So velocity = 1.5 m / 1.392 s = 1.08 m/s

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3 years ago

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Shtirlitz [24]

Explanation:

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Wind is the result of pressure changes in the atmosphere due to temperature.

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3 years ago

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Montano1993 [528]

Density is varying through the world’s oceans. The density of ocean water is not uniform.

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4 years ago