Atoms containing radioactive nuclei are called

Find initial velocity and time in air

kkurt [141]

Answer:

The answer to your question is: v = 121.46 m/s

Explanation:

Data

h = 30 m

vo = ?

dx = 300 m

Formula

t = $\sqrt{\frac{2h}{g}}$

speed = distance / time

Process

$t = \sqrt{\frac{2(30)}{9.81}} \\$

t= 2.47 s

speed = 300 / 2.47

speed = v = 121.46 m/s

6 0

3 years ago

Three students are having a conversation. It goes like this. Allison says: "This problem says, can you add a resistor to the cir

notsponge [240]

Answer:

Nima and Natasha are absolutely correct.

Explanation:

When connecting two resistors in series, their resistances add:

$R_{eq}=R_{1}+R_{2}$

which means that whenever we add a resistance in series, their magnitudes will add, giving us a resistance that is greater than the original resistance, which will demand less current from the battery because of ohm's law:

$I=\frac{V}{R}$

So, the greater the resistance, the smaller the current.

When connecting two resistors in parallel, the reciprocal of ther resistances add:

$\frac{1}{R_{eq}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}$

or

$R_{eq}=\frac{R_{1}R_{2}}{R_{1}+R_{2}}$

The equivalent resistance will always be less than the smallest resistor in the circuit, so the equivalent resistance will always decrease as more resistors are added. A decrease in the resistance means that the current will increase.

8 0

3 years ago

A DC current of 60 mA can cause paralysis of the body's respiratory muscles and hence interfere with breathing, but only 15 mA (

Liula [17]

To solve this problem it is necessary to apply the concepts related to Ohm's Law to find the voltage in the case of direct current. While for the Alternate current we use the concept of RMS voltage.

PART A) In the case of DC we have to,

V=IR

Where,

I = Current

R = Resistance

Where the current is 60mA y the resistance is $1000\Omega$ , then the potential would be

$V=(60mA)(1100\Omega)$

$V = 66V$

In the case of DC we have that the current and the RMS voltage is,

$I_{rms} = 15 mA$

$R = 1100 \Omega$

$V_{rms} = 16.5 V$

The potential in AC then is,

$V_o = \sqrt{2}V_{rms}$

$V_o = \sqrt{2}(16.5)$

$V_o = 23.3345 V$

3 0

3 years ago

Suppose the first coil of wire illustrated in the simulation is wound around the iron core 7 times. Suppose the second coil is w

SVETLANKA909090 [29]

Answer:

Emf induced in the coli will be equal to 26 volt

Explanation:

We have given number of turns N = 13

It is given that magnetic flux changes from 2.1 Weber to 2.7 Weber in 0.3 sec

Change in flux $d\Phi =2.7-2.1=0.6Weber$

Change in time dt = 0.3 sec

We have to find the induced emf

Induced emf is equal to $e=N\frac{d\Phi }{dt}=13\times \frac{0.6}{0.3}=26volt$

So emf induced in the coil will be equal to 6 volt

5 0

3 years ago

Read 2 more answers

if a body of mass 2kg moving with Velocity of 15m/s collides with a stationary body of same mass then after elastic collision 2n

pochemuha

Answer:

v = 15 [m/s]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is equal to the product of mass by Velocity.

$P=m*v$

where:

P = linear momentum [kg*m/s]

m = mass = 2 [kg]

v = velocity = 15 [m/s]

$P=2*15\\P=30 [kg*m/s]$

Since we know that momentum is conserved, that is, all momentum is transferred to the second body, we can determine the velocity of the second body, since the mass is equal to that of the first body.

$30=2*v\\v = 30/2\\v = 15 [m/s]$

5 0

3 years ago