Answer:
The current would be same in both situation.
Explanation:
Given that,
Current I = 13 A
Number of turns = 23
We need to calculate the induced emf
Using formula of induced emf is

For N = 1

We need to calculate the current
Using formula of current

Put the value of emf

Now, if the number of turn is 22 , then induced emf would be

Then the current would be




Hence, The current would be same in both situation.
Answer:
41.74 m/s
Explanation:
The energy used to draw the bowstring = the kinetic energy of the arrow.
Fd = 1/2mv²................................ Equation 1
Where F = force, d = distance move string, m = mass of the arrow, v = speed of the arrow.
make v the subject of the equation
v = √(2Fd/m)...................... Equation 2
Given: F = 201 N, m = 0.3 kg, d = 1.3 m.
Substitute into equation 2
v = √(2×201×1.3/0.3)
v = √(1742)
v = 41.74 m/s.
Hence the arrow leave the bow with a speed of 41.74 m/s
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Answer:
Mercury:
.85
pea
Venus:
2.1
gumball
Earth:
2.2
gumball
Mars:
1.2
marble
Uranus:
9
grapefruit
Neptune:
8.6
softball
Explanation:
I have no clue if I'm right but hopefully, I am
Answer:
mass is in kg and velocity is in m/s for the answer to be in Joules
Explanation: