Answer:
a) 10.54 sec
b) 284.58 m
c) 29.406 m/s
d) 39.92 m/s
Explanation:
Given data:
velocity of spacecraft = 27.0 m/s
rate of free fall acceleration is 2.79 m/s^2
distance of moving aircraft from mooon surface is 155 m
a. from kinematic eqaution of motion we have
where y = 155 m
Vi = 0 as this relation is for vertical motion, so the 27.0 m/s is not included
and a = 2.79 m/s^2.
Solving for t we get
t = 10.54 sec
b.
we know that 
c. from the kinematic formula
v = u + at
v = 29.4066 m/a
d. 
v = 39.92 m/s
an animal that feeds on carrion, dead plant material, or refuse
Answer:
The torque must be supplied by the motor to keep the wheel rotating at a constant angular velocity is 12 N-m.
Explanation:
Given that,
The coefficient of kinetic friction with the wheel is 0.60
Force acting against the wheel, F = 40 N
Let the distance is, r = 0.5 m
Torque is given by the product of force and distance. Here, the force will be :
Torque is given by :
So, the torque must be supplied by the motor to keep the wheel rotating at a constant angular velocity is 12 N-m.
It might mean that there is balance in rainfall and evaporation.
Alpha is weak and cannot pass through paper so it’s only hazardous and very close distances
beta is a bit stronger but will not be very hazardous at long distances unless there’s aluminium them u can stand next to it
gamma is very hazardous and can be dangerous at basically any distance ig yesh you need alotta protection
