Answer:
6.18% of the class has an exam score of A- or higher.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What percentage of the class has an exam score of A- or higher (defined as at least 90)?
This is 1 subtracted by the pvalue of Z when X = 90. So



has a pvalue of 0.9382
1 - 0.9382 = 0.0618
6.18% of the class has an exam score of A- or higher.
No it was not correct because if there is 12 inches in one foot and you divid 150 by 12 you get 12.6. Then you would multiply 12.6 and .15 and you would get 20.40. So you were charged extra with out tax.
Answer:
c
Step-by-step explanation:
9:12, 18:24,6:8
3*3=9 and 4*3=12
3*6=18 and 4*6=24
3*2=6 and 4*2=8
2x-5=x+2
x=7
The answer is 7