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Naily [24]
3 years ago
11

-4p-(1-6p) help please

Mathematics
2 answers:
Veronika [31]3 years ago
6 0
-4p -1 + 6p

-4p + 6p - 1

2p - 1
tatiyna3 years ago
3 0
1) Pretend there is an invisible -1 in front of the parenthesis to <em>distribute</em> and get rid of the parenthesis.

-4p-(1-6p) = -4p-1+6p

Now <em>combine like terms.</em>

 -4p+6p = 2p and -1=-1.
 
Since there is no = sign, the answer should probably remain

2p-1





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DOES ANYONE KNOW THIS
GREYUIT [131]

Answer: 13 players.


Step-by-step explanation:

1. Let's call:

 x: Price of the shirt (x=17)

 y: Price of socks  y=5.50

 n: number of players.

2. You know that the budget is $300 and you have the following formula given in the problem:

n(x+y)\leq300

3. Substitute values and solve for n.Then, you obtain the following result:

n(17+5.50)\leq300\\22.5n\leq300\\n\leq13.33

4. The answer is: 13 players.

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3 years ago
Find the equation of the line with a slope of -3, passing through the point (2,5).
Alexxx [7]
Y = -3(2) + 11
y = -6 + 11
y = 5

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Use substitution to solve the system of equations.<br><br><br> 28 = x – 7y<br> –3x + 9 =4y
Serggg [28]
The answer is (7,-3)
5 0
2 years ago
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What is the next two terms of 2,4,6,24,26
Dmitrij [34]

Answer:

108 and 110

Step-by-step explanation:

because the pattern is multiply by 4, then add 2

4 0
2 years ago
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Help appreciated on question in image!<br> Thanks:)
Verdich [7]

Answer:

x=-1,\:x=-7,\:x=i,\:x=-i

Step-by-step explanation:

Considering the equation

x^4+8x^3+8x^2+8x+7=0

Solving

x^4+8x^3+8x^2+8x+7

\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)

As

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=7,\:\quad a_n=1

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]

Solving

\frac{x^4+8x^3+8x^2+8x+7}{x+1}

=x^3+7x^2+x+7

Putting \frac{x^4+8x^3+8x^2+8x+7}{x+1} =  x^3+7x^2+x+7 in equation [A]

So,

\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]

=\left(x+1\right)x^3+7x^2+x+7

As

x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)

So,

Equation [A] becomes

=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)

So,  the polynomial equation becomes

\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)\mathrm{Solve\:}\:x+1=0:\quad x=-1

\mathrm{Solve\:}\:x+7=0:\quad x=-7

\mathrm{Solve\:}\:x^2+1=0:\quad x=i,\:x=-i

\mathrm{The\:solutions\:are}

x=-1,\:x=-7,\:x=i,\:x=-i

Keywords: polynomial equation

Learn polynomial equation from brainly.com/question/12240569

#learnwithBrainly

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