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Ann [662]
4 years ago
13

Which of the following describes the zeroes of the graph of f(x) = 3x6 + 30x5 + 75x4?

Mathematics
2 answers:
Snezhnost [94]4 years ago
6 0
F(x) = 3x^6 + 30x^5 +75x^4
Factoring  3x^4(x^2 +10x + 25) = 3x^4(x+5)(x+5) = 0
x = 0, -5 with -5 having a multiplicity of 2 are the zeroes.
DENIUS [597]4 years ago
3 0
ANSWER

The zeros are:
x = 0 \: \: or \: \: x = - 5
with multiplicity of 4 and 2 respectively.


EXPLANATION

The given function is

f(x) =3 {x}^{6} + 30 {x}^{5} + 75 {x}^{4}
We want to find

3 {x}^{6} + 30 {x}^{5} + 75 {x}^{4} = 0

We can find the zeros of this function by factorizing the greatest common factor to obtain,

3 {x}^{4} ( {x}^{2} + 10x + 25) = 0

The expression in the bracket can be rewritten as,

3 {x}^{4} ( {x}^{2} + 2(5)x + {5}^{2} ) = 0

We can see clearly that, the expression in the bracket is a perfect square that can be factored as,

3 {x}^{4} ( x+ 5)^2 = 0

This implies that,

3 {x}^{4} = 0
or

(x + 5) ^{2} = 0

This gives,

{x}^{4} = 0 \: \: or \: \: x + 5 = 0

This finally gives,

x = 0 \: \: or \: \: x = - 5
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TRIGONOMETRY - Given the complex numbers <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D20%20cis%20226" id="TexFormula1" title
Norma-Jean [14]

This is easily done after writing both complex numbers in exponential form:

z_1=20\,\mathrm{cis}226^\circ=20e^{226^\circ i}

z_2=5\,\mathrm{cis}76^\circ=5e^{76^\circ i}

Then

\dfrac{z_1}{z_2}=\dfrac{20e^{226^\circ i}}{5e^{76^\circ i}}=4e^{(226-76)^\circ i}=4e^{150^\circ i}

In trigonometric form, this is

\dfrac{z_1}{z_2}=4\,\mathrm{cis}150^\circ=4(\cos150^\circ+i\sin150^\circ)=\boxed{-\dfrac{\sqrt3}2+\dfrac i2}

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3 years ago
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Here you go:

1) 0.3 = 3/10
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Please mark as Brainliest, I want to rank up :D
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