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dedylja [7]
4 years ago
5

4b^2-64/-4b+16 please help me i am stupid as all get out

Mathematics
1 answer:
AVprozaik [17]4 years ago
8 0
It could be 5(8*7)4* it could be ok
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Use the long division method to find the result when 6x^3 + 19x2^2 + 17x + 3 is
skelet666 [1.2K]

Answer:

\frac{6x^3 \ + \ 19x^2 \ + \ 17x \ + \ 3}{2x \ + \ 3}  \ = \ 3x^2 \ + \ 5x \ + \ 1

Step-by-step explanation:

Given;

F(x) = 6x³  +  19x²   +   17x   +  3

Factor of F(x) = 2x + 3

Using long division method;

                                   3x²  + 5x  +   1

                                 ------------------------------------

               2x + 3    √  6x³  +  19x²   +   17x   +  3

                             -  (6x³   +   9x²)

                                ----------------------------------------

                                               10x²    +    17x   +  3

                                          -   (10x²     + 15x)

                                             -------------------------------

                                                                  2x   +  3

                                                               - (2x   +  3)

                                                                 ---------------

                                                                         0

Thus, \frac{6x^3 \ + \ 19x^2 \ + \ 17x \ + \ 3}{2x \ + \ 3}  \ = 3x^2 \ + \ 5x \ + \ 1

                       

8 0
3 years ago
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