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dedylja [7]
3 years ago
5

4b^2-64/-4b+16 please help me i am stupid as all get out

Mathematics
1 answer:
AVprozaik [17]3 years ago
8 0
It could be 5(8*7)4* it could be ok
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Negative four and one third ÷ two and one fifth
3241004551 [841]

The solution to the given expression negative four and one third ÷ two and one fifth is -1 32/33

<h3>Fraction division</h3>

negative four and one third ÷ two and one fifth

-4 1/3 ÷ 2 1/5

= -13/3 ÷ 11/5

  • Multiply by the reciprocal of 11/5

  • The reciprocal of 11/5 is 5/11

= -13/3 × 5/11

= (-13 × 5) / (3 × 11)

= -65 / 33

= -1 32/33

Therefore, the solution to the fraction is -1 32/33

Learn more about fraction:

brainly.com/question/11562149

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5 0
1 year ago
Read 2 more answers
-2+0=? pleaseee help 10pointsss
Luba_88 [7]
-2 is the correct answer.
8 0
3 years ago
Read 2 more answers
Melissa wants to check the accuracy the accuracy of the finance charge on her promissory note. She has a $6000, four-year loan a
ValentinkaMS [17]

Answer:

1. Melissa wants to check the accuracy of the finance charge on her promissory note. She has a $6,000, 4-year loan at an APR of 3.11%.

What is her monthly payment?

$133.10

5 0
3 years ago
What is the best first step in solving the equation 3+√6x=5?
AleksAgata [21]
Cube both sides
remember PEMDAS
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3 0
2 years ago
The sum of two integers is 26. the sum of the squares of the two integers is 340. what is the product of the two numbers?
Phoenix [80]
Lets say that the two unknown integers are n and m.

We know the following things about n and m:

n+m=26
n^2+m^2=340

And, we want to find nm.

To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:

(n+m)^2=n^2+2nm+m^2

So, given what we know about the unknown integers, the previous can be written as:

(26)^2=340+2nm

We can easily solve for nm:

nm= \frac{(26)^2-340}{2}= \frac{676-340}{2}= \frac{336}{2}=168

The answer is 168.

Another approach to solve the problem is, from the two starting equations, compute the values of n and m, which are 12 and 14, and directly compute their product; however, the approach described is more elegant. 
5 0
3 years ago
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