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Rina8888 [55]
4 years ago
13

An air-track glider undergoes a perfectly inelastic collision with an identical glider that is initially at rest. what fraction

of the first glider's initial kinetic energy is transformed into thermal energy in this collision?

Physics
2 answers:
Mashutka [201]4 years ago
6 0

Half of the first glider's initial kinetic energy is transformed into thermal energy in this collision.

\texttt{ }

<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

\large {\boxed {F = ma }

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of first glider = m₁ = m

mass of second glider = m₂ = m

initial speed of first glider = u₁ = u

initial speed of second glider = u₂ = 0

final speed of both gliders = v₁ = v₂ = v <em>→ perfectly inelatic collision</em>

<u>Asked:</u>

change in kinetic energy = ΔEk = ?

<u>Solution:</u>

<em>Firstly , we will use </em><em>Conservation of Momentum Law </em><em>as follows:</em>

m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2

mu + m(0) = mv + mv

mu = 2mv

u = 2v

\boxed {v = \frac{1}{2}u}

\texttt{ }

<em>Next , we could calculate the change in kinetic energy of first glider:</em>

\Delta Ek : Ek_1 = ( Ek_1 - Ek ) : Ek_1

\Delta Ek : Ek_1 = ( \frac{1}{2}mu^2 - \frac{1}{2}(2mv^2)) : (\frac{1}{2}mu^2)

\Delta Ek : Ek_1 = ( mu^2 - 2mv^2 ) : (mu^2)

\Delta Ek : Ek_1 = ( mu^2 - 2m(\frac{1}{2}u)^2 ) : (mu^2)

\Delta Ek : Ek_1 = ( mu^2 - 2m(\frac{1}{4}u^2) ) : (mu^2)

\Delta Ek : Ek_1 = ( mu^2 - \frac{1}{2}mu^2 ) : (mu^2)

\Delta Ek : Ek_1 = ( \frac{1}{2}mu^2 ) : (mu^2)

\Delta Ek : Ek_1 = \frac{1}{2} : 1

\boxed {\Delta Ek = \frac{1}{2} Ek_1}

\texttt{ }

<h3>Conclusion:</h3>

Half of the first glider's initial kinetic energy is transformed into thermal energy in this collision.

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

DiKsa [7]4 years ago
5 0
Refer to the diagram shown below.

The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²

After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2

The final KE is
KE₂ = (1/2)(2m)v²
       = m(u/2)²
       = (1/4)mu²
      = (1/2) KE₁

The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.

Conservation of energy requires that the loss in KE be accounted for as thermal energy.

Answer:  1/2 

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Hello. This question is incomplete. The full question is:

A conducting sphere contains positive charge distributed uniformly over its surface. Which statements about the potential due to this sphere are true? All potentials are measured relative to infinity. (There may be more than one correct choice.)

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C) The potential at the center of the sphere is the same as the potential at the surface.

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