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In-s [12.5K]
3 years ago
9

What is the butterfly effect?

Physics
1 answer:
Reil [10]3 years ago
7 0

Answer:

In chaos theory , the butterfly effect is the sensetive dependence on initial conditions in which a small change in one state of a deterministic nonlinear can result in large difference in a letter state.

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allochka39001 [22]

increaskng the impulse also <u>increases </u><u>momentum</u>

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What is the main evidence for the structure of the Earth that occur from the generation of an earthquake?
xeze [42]
I believe that its waves

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The imidazole side chain of histidine has a pka of 6.04. illustrate the predominant structures for histidine at (i) ph 4, (ii) p
Advocard [28]

The histidine imidazole side chain has a pka of 6.04. To illustrate the predominant structures for histidine at (i) ph 4, (ii) ph 8, and (iii) ph 12, we have the pictures attached below. The first one indicates structure at ph 4, second one indicates ph 8 and third indicates ph 12.

<h3>What is stereochemistry? </h3>

The study of stereochemistry is focused on stereoisomers, which by definition have the same molecular formula and sequence of bonded atoms (constitution) but differ in the three-dimensional orientations of their atoms in space.

Stereochemistry is a subfield of chemistry that deals with the relative spatial arrangement of atoms that form the structure of molecules and their manipulation. Because the prefix “stereo- “denotes “three-dimensionality,” it is also referred to as “3D chemistry.”

One crucial area of stereochemistry is the study of chiral molecules. Stereochemistry covers the entire range of organic, inorganic, biological, physical, and particularly supramolecular chemistry.

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To know more about imidazole side chain, Visit:

brainly.com/question/14691147

#SPJ4

5 0
1 year ago
A spring with a spring constant of 1730 N/m is compressed 0.136 m from its equilibrium position with an object having a mass of
Elan Coil [88]

Given :

A spring with a spring constant of 1730 N/m is compressed 0.136 m from its equilibrium position with an object having a mass of 1.72 kg.

To Find :

The embankment in the height.

Solution :

Since no external force is acting in the system, therefore total energy will be conserved.

Initial kinetic energy of the object = Energy stored in spring

K.E _i = \dfrac{kx^2}{2}\\\\K.E_i = \dfrac{1730\times 0.136^2}{2}\\\\K.E_i = 16\ J

Also, initial potential energy is 0.

Now,

K.E_i + P.E_i = K.E_f + P.E_f\\\\16 + 0 = \dfrac{1.72\times 2.45^2}{2}+ mgh\\\\mgh =16 - 5.16\\\\h = \dfrac{16 - 5.16}{1.72 \times 9.8}\\\\h = 0.64\ m

Therefore, the embankment height is 0.64 m.

3 0
3 years ago
A bowling ball weighing 71.2 N (16.0 lb) is attached to the ceiling by a 3.80-m rope. The ball is pulled to one side and release
Elina [12.6K]

Answer:

a) For this case we want to find the acceleration of the bowling ball, and we now that the only acceleration for this case would be the centrifugal acceleration becuase since the pendulum is in phase with the equilibrium point the tangential acceleration is 0, and if we find the centrifugal acceleration we got:

a= \frac{v^2}{R}= \frac{(4.2 m/s)^2}{3.8 m}=4.64 m/s^2

b) For this case the tendsion is an opposite force against the weight and the centrifugal force acting in the ball so then we can find the tension like this:

T= mg +ma

In order to find the mass we know that W=mg and solving for m we got:

m =\frac{W}{g}=\frac{71.2 N}{9.8 m/s^2}=7.265 kg

And replacing into the tension we got:

T= m(g+a) =7.265 kg *(9.8 m/s^2 +4.64 m/s^2)=104.907 N

Explanation:

For this case we have the following data given:

W= 71.2 N represent the weigth for the object

R=3.8 m the length of the rope or the radius

v= 4.2 m/s represent the velocity of the bowling ball

Part a

For this case we want to find the acceleration of the bowling ball, and we now that the only acceleration for this case would be the centrifugal acceleration becuase since the pendulum is in phase with the equilibrium point the tangential acceleration is 0, and if we find the centrifugal acceleration we got:

a= \frac{v^2}{R}= \frac{(4.2 m/s)^2}{3.8 m}=4.64 m/s^2

Part b

For this case the tendsion is an opposite force against the weight and the centrifugal force acting in the ball so then we can find the tension like this:

T= mg +ma

In order to find the mass we know that W=mg and solving for m we got:

m =\frac{W}{g}=\frac{71.2 N}{9.8 m/s^2}=7.265 kg

And replacing into the tension we got:

T= m(g+a) =7.265 kg *(9.8 m/s^2 +4.64 m/s^2)=104.907 N

7 0
3 years ago
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