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fredd [130]
3 years ago
15

If a balloon is squeezed, what happens to the pressure of the gas inside the balloon?

Physics
1 answer:
miss Akunina [59]3 years ago
6 0

Answer:   By squeezing the balloon, you reduce the space the gas particles can occupy. As the particles are pushed a bit closer together, they collide with more, so the pressure from the moving gas particles increases. If the volume increases, its pressure decreases.

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The force that pulls falling objects toward Earth is called *
larisa [96]

Answer:

Gravity

Explanation:

That's easy because gravity is the only thing that can pull us down that hard at that fast without anything helping it.

5 0
3 years ago
Which of the following is not a property of displacement?
NNADVOKAT [17]

Answer:

Your correct answer is option C. Displacement is equal to the total distance traveled by an object in motion.

Explanation:

This is something that is definitely not a displacement.

4 0
4 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!
liq [111]

Answer:

r = 0.37 m

Explanation:

Use Coulomb's law to solve for r:

F = kq1q2/r^2

---> r^2 = kq1q2/F

= (8.99×10^9)(5.6×10^-4)(-2.1×10^-4)/(-7.7×10^3)

= 0.1373 m^2

or r = 0.37 m

4 0
3 years ago
A uniform ladder of length 10.8 m is leaning against a vertical frictionless wall. The weight of the ladder is 323 N, and it mak
love history [14]

Answer:

0.3625

Explanation:

From the given information:

Consider the equilibrium conditions;

On the ladder, net torque= 0

Thus,

\tau_{net} = 0; and

-fL \s in \theta +m_L g \dfrac{L}{2} cos \theta + mg (7.46\ m) cos \theta = 0

However, by rearrangement;

fL \s in \theta =m_L g \dfrac{L}{2} cos \theta + mg (7.46\ m) cos \theta  \\ \\  \mu(m_L + m) gL \ sin \theta = (323  \ N) ( 10.8 \ meters) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos  \  66.46^0

\mu= \dfrac{ (323  \ N) ( 10.8 \ m) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos  \  66.46^0}{\Big [(323 \ N)+(734 \ N) \Big] (10.8 \ m)}

\mathbf{\mu= 0.3625 }

8 0
3 years ago
a ball (mas .40) is initially moving to the left at 30m/s. After hitting the wall, the ball is moving to the right at 20 m/s. Wh
Step2247 [10]

Answer:

The impulse is -20kg m/s.

Explanation:

given mass of ball =  0.4 kg

The ball is moving towards left with the initial velocity = 30m/s

The momentum in left direction P1 = mv1

= (0.4)(30)

= 12 kg m/s

The given velocity towards right = -20 m/s ( negative sign shows inverse direction)

Momentum towards right, P2 = mv2

P2 = (0.4)(-20)

P2 = -8 kg m/s

The Impulse = change in momentum

= P2 –P1

= -8-12

= -20 kg m/s

6 0
4 years ago
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