If 400 Joules of work is done in 20 seconds, how much power was generated?

Astatine-210 has a half-life of 8.08 days. What fraction of a sample of astatine-210 is left unchanged after 16.16 days?

Flauer [41]

Answer:

0

Explanation:

Given parameters:

Half-life = 8.08days

Unknown:

What fraction is left unchanged after 16.16days = ?

Solution:

The half - life of a substance is the time taken for the half of a radioactive material to decay to half.

Day 0 Day 8.08 Day 16.16

100% 50% 0% Parent

0% 50% 100% Daughter

After 16.16 days, non of the original sample will remain unchanged.

6 0

3 years ago

I am very confused, our teacher didn’t properly teach us this. How do you do it?

Fudgin [204]

Answer:

You multiply the 3 numbers together to get your volume, in this case it would be 4058.488 cm^3 (cm cubed)

so

V: 4058.488cm^3 ( round up to 4058.5 for convenience)

M: 27579

D: ?

So we divide mass by the volume to get density, which is

27579 / 4058.5 = ~6.79536 (can round up to 7 or 6.8)

This graph can help a lot, so maybe try and memorize it, hope I helped.

3 0

3 years ago

Read 2 more answers

A car with a mass of 1,200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. The centri

Helga [31]

The answer is 80 m.

Centripetal force (F) is a force that makes body move around a circular curve. The unit of force is N (N = kg * m/s²).
It can be represented as:
$F= \frac{m* v^{2} }{r}$
where:
m - mass
v - velocity
r - radius of the curve

We have:
m = 1,200 kg
V = 20 m/s
F = 6,000 N = 6,000 kg * m/s²

We need radius of the curve:
r = ?

So, if <span> $F= \frac{m* v^{2} }{r}$ , then:
</span> $r= \frac{3* v^{2} }{F}$
⇒ $r = \frac{1200 kg * (20m/s)^{2} }{6000 kg*m/s^{2} }$
⇒ $r= \frac{1200*400*kg*m^{2}*s^{2} }{6000kg*m/s^{2} }$
⇒ $r= \frac{480,000m}{6000}$
⇒ $r=80m$

6 0

3 years ago

6. El oxígeno gaseoso se calienta a presión constate de 50 °C a 300 K. Se conoce que inicialmente el volumen del sistema era de

frez [133]

Answer:

El volumen final del sistema es 1.2L

Explanation:

La ley de Charles establece que el incremento de la temperatura de un gas produce un incremento en el volumen directamente proporcional cuando la presión permanece constante. La ecuación es:

V₁/T₁ = V₂/T₂

<em>Donde V es volumen y T temperatura absoluta de un gas en 1, el estado inicial y 2, su estado final.</em>

<em />

Reemplazando:

V₁ = 1.3L

T₁ = 50°C + 273.15K = 323.15K

V₂ = Incógnita

T₂ = 300K

1.3L/323.15K = V₂/300K

1.2L = V₂

<h3>El volumen final del sistema es 1.2L</h3>

3 0

3 years ago

A sample of ideal gas has a volume of 0.500-L at 25.0o C and 1.20 atm pressure. What is the volume at 75.0o C and 3.60 atm?

sergeinik [125]

Answer:

.500

Explanation:

Use the ideal gas law equation: PV = nRT

Plug in the initial values given:

P = 1.2 atm

V = .500 L

n = number of moles

R = Gas Constant 8.314

T = 25.0 C

(1.2)(.5) = n(8.314)(25)

solving for n we get .00289

Now use the same equation with the new values solving for V

(3.6)V = (.00289)(8.314)(75.0)

V = .4999999 ROund to .500

3 0

3 years ago