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nadezda [96]
3 years ago
12

6. El oxígeno gaseoso se calienta a presión constate de 50 °C a 300 K. Se conoce que inicialmente el volumen del sistema era de

1,3 litros. ¿Cuál es el volumen final del sistema?
Chemistry
1 answer:
frez [133]3 years ago
3 0

Answer:

El volumen final del sistema es 1.2L

Explanation:

La ley de Charles establece que el incremento de la temperatura de un gas produce un incremento en el volumen directamente proporcional cuando la presión permanece constante. La ecuación es:

V₁/T₁ = V₂/T₂

<em>Donde V es volumen y T temperatura absoluta de un gas en 1, el estado inicial y 2, su estado final.</em>

<em />

Reemplazando:

V₁ = 1.3L

T₁ = 50°C + 273.15K = 323.15K

V₂ = Incógnita

T₂ = 300K

1.3L/323.15K = V₂/300K

1.2L = V₂

<h3>El volumen final del sistema es 1.2L</h3>
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Answer:

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3 years ago
179.1 g of water is in a Styrofoam calorimeter of negligible heat capacity. The initial T of the water is 16.1oC. After 306.9 g
taurus [48]

Answer:

the specific heat of the unknown compound is c_u=0.412J/g \cdot C

Explanation:

Generally the change in temperature of water is evaluated as

                \Delta T = T_2 -T_1

Substituting 16.1°C for T_1 and 27.4°C for T_2

                \Delta T = 27.4 - 16.1

                       =11.3^oC

Generally the change in temperature of  unknown compound is evaluated as

                  \Delta T_u = T_3 -T_2

Substituting 27.4°C for T_2 and 94.3°C for T_3

                                    \Delta T = 94.3 - 27.4

                                           =66.9^oC

Since there is an increase in temperature then heat is gained by water and this can be evaluated as

               H_w = mc_w \Delta T

Substituting 179.1 g  for m , 4.18 J/g.C for c_w(specific heat of water)

             H_w = 4.18 * 179.1 * 11.3

                   = 8459.6J

Since there is a decrease in temperature then heat is lost by unknown compound and this can be evaluated as

                    H_u = m_uc_u \Delta T_u

By conservation of energy law

       Heat lost  = Heat gained  

Substituting 306.9 g  for m_u , 8459.6J for H_u

           8459.6 = 306.9 * c_u * 66.9

  Therefore     c_u = \frac{8459.6}{308.9 *66.9}

                           =0.412J/g \cdot C

                   

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3 years ago
How many molecules are in 5.00 grams of NH3
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Answer:

0.293590565643325

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A 35 L tank of oxygen is at 315 K with an internal pressure of 190 atmospheres. How
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Answer:

600.7 moles

Explanation:

Applying,

PV = nRT................... Equation 1

Where P = Pressure of oxygen, V = Volume of oxygen, n = number of moles, R = molar gas constant, T = Temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

From the question,

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Substitute these values into equation 2

n = (190×35)/(135×0.082)

n = 600.7 moles of xygen

6 0
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