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Cerrena [4.2K]
3 years ago
14

What types of intermolecular interactions are present in pure substances composed of the each of the three molecules below:

Chemistry
1 answer:
Dmitriy789 [7]3 years ago
3 0

Answer:

1. Dipole-Dipole

2. Hydrogen bonding

3. London dispersion forces

Explanation:

- First, you need to be familiar with each of these terms.

- Secondly, you need to know how to calculate electron negetivity.

Once you know both of these things, all you do is match the defintions.

- Hope this helps! If you would like me to thoroughly explain this to you please let me know, as I would be glad to do it.

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An unknown substance has been shown to have metallic bonds.
gladu [14]
This is the correct answer please mark me as brainliest

6 0
3 years ago
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The mass of cupric sulfate needed to make .5 liters of a .5M solution is
dalvyx [7]

Answer:

C

Explanation:

3 0
3 years ago
When radium-226 (atomic number-88) decays by emitting an alpha particle it becomes _____.
topjm [15]

Answer:

d. Radon-222

Explanation:

²²⁶₈₈Ra → ²²²₈₆Rn  + ⁴₂He

Alpha particle is a helium nucleus with mass number 4 and atomic number 2. According to the law of conversation of mass, the sum of the mass number and atomic number must be equal on both side of the reaction.  

Since the mass number of Ra is 226 and that of He is 4. The mass number of the unknown element must be 226 - 4 = 222.  

Since the atomic number of Ra is 88 and that of He is 2. The atomic number of the unknown element must be 88 - 2 = 86.  

Now looking in the periodic table Radon is the only element with atomic number 86.  

3 0
3 years ago
What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
Montano1993 [528]

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

4 0
3 years ago
represent rutheniums first 36 electrons using the chemical symbol for krypton written inside the brackets
kirza4 [7]

Answer:

[kr] hd^75s^1

Explanation:

7 0
3 years ago
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