Answer: Correct options are as follows.
- salt is not chemically bonded to water.
- salt and water retain their own chemical properties.
Explanation:
When salt is dissolved in water then it means that it is a physical change as salt has completely dissociated into ions but they are not chemically combined to the water molecules.
As a result, both salt and water will retain their chemical properties.
For example, NaCl when dissolved in water will dissociate as follows.
Only the particles of salt have evenly distributed in water.
And, when a components of a salt chemically combine with another substance then it will form a new compound.
Therefore, we can conclude that salt dissolved in water is a solution, therefore:
- salt is not chemically bonded to water.
- salt and water retain their own chemical properties.
Answer:
There's a very small difference between the two...a compound is when you mix several elements to create a whole new one. A mixture is when you mix several elements together, but instead of it creating a completely different compound, it's simply just a few elements mixed together.
Answer:
4.42x10⁻¹⁹ J/molecule
Explanation:
At a double bond, there's sigma and a pi bond, and at a single bond, there's only a sigma bond. Thus, if the energy to break both sigma and pi is 614 kJ/mol, and the energy to break only the sigma bond is 348 kJ/mol, the energy to break only the pi bond is:
E = 614 - 348 = 266 kJ/mol
Knowing that 1 kJ = 1000 J, E = 266,000 J/mol
By Avogadro's number, 1 mol = 6.02x10²³ molecules, thus:
E = 266,000 J/mol * 1mol/6.02x10²³ molecules
E = 4.42x10⁻¹⁹ J/molecule
Answer:
NH4Cl, NaCl, Ba(OH)2, NaOH
Explanation:
NH4Cl is an acidic salt formed by the neutralization of a strong acid (HCl) with a weak base (NH3). Hence, it will habe a PH<7 (the lowest PH).
NaCl is a neutral salt,formed by neutralization of a strong acid (HCl) with a strong base (NaOH). Hence, it will have a PH of 7.
Ba(OH)2 is a weak base. Therefore, it will have a PH between 8 and 10.
NaOh meanwhile, is a strong base. Therefore, it will have a PH between 10 to 13.
Hence, we have
NH4Cl < NaCl < Ba(OH)2 < NaOH
Answer:
643g of methane will there be in the room
Explanation:
To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -<em>Assuming STP-</em>. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:
<em>Volume Methane:</em>
3600s * (0.25L / s) = 900L Methane
<em>Moles methane:</em>
PV = nRT; PV / RT = n
<em>Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP</em>
Replacing:
PV / RT = n
1atm*900L / 0.082atmL/molK*273.15 = n
n = 40.18mol methane
<em>Mass methane:</em>
40.18 moles * (16g/mol) =
<h3>643g of methane will there be in the room</h3>
