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Paha777 [63]
3 years ago
8

A sample of ideal gas has a volume of 0.500-L at 25.0o C and 1.20 atm pressure. What is the volume at 75.0o C and 3.60 atm?

Chemistry
1 answer:
sergeinik [125]3 years ago
3 0

Answer:

.500

Explanation:

Use the ideal gas law equation: PV = nRT

Plug in the initial values given:

P = 1.2 atm

V = .500 L

n = number of moles

R = Gas Constant 8.314

T = 25.0 C

(1.2)(.5) = n(8.314)(25)

solving for n we get .00289

Now use the same equation with the new values solving for V

(3.6)V = (.00289)(8.314)(75.0)

V = .4999999 ROund to .500

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An alcohol as n-octyl alcohol has different polarity than an alkene as 1-octene.

Thus, using  thin layer chromatography is most easy to separate:

<em>B. n-octyl alcohol and 1-octene </em>

<em></em>

I hope it helps!

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54.0 g Al reacts with 64.0 g O2 to
Stells [14]

Answer:

102 g Al₂O₃

Explanation:

To find the mass of Al₂O₃, you need to (1) convert grams Al to moles Al (via molar mass), then (2) convert moles Al to moles Al₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Al₂O₃ to grams Al₂O₃ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given values.

Molar Mass (Al): 26.98 g/mol

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4 Al + 3 O₂ ---> 2 Al₂O₃

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--------------  x  -----------------  x  -----------------------  x  ----------------  =  102 g Al₂O₃
                        26.98 g               4 moles Al            1 mole

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