Answer:
Explanation:
Given data:
weigh (head+arms + head) w_1 = 438 N
centre of gravity y_1= 1.28 m
weigh (upper leg) w_2 = 144 N
Center of gravity y_2 = 0.760 m
weigh ( lower leg + feet) = 87 N
centre of gravity = y_3 = 0.250 m
location of center of gravity 
Answer:
Time= 6.12*10^4s
mass flow rate m=0.98kg/s
Explanation:
Given
Volume= 60m^3
diamter= 2.5cm= 0.025m
radius= 0.0125m
area A= πr^2
area A= 3.142*0.0125^2
area A= 4.9*10^-4m^2
the velocity of the flow 2m/s
<u>volume flow rate </u>
V=vA
V=2* 4.9*10^-4
V=9.82*10^-4 m^3/s
<u>Time taken to fill the pool</u>
time= volume/volume flow rate
time= 60/9.82*10^-4
time= 6.12*10^4s
<u>Mass flow rate </u>
m= density *volume flow rate
Assuming the density of water to be 997kg/m^3
m= 997*9.82*10^-4
m=0.98kg/s
The ardor determines the result of a reaction.
[formula A]+[formula B]—> [formula C]
Here, the arrow signifies that when adding formula A and B, you get formula C. An arrow can also go both directions.
[formulaA]+[form.B]<—>[formulaC]+[form.D]
Here, the double sided arrows means that adding formulas A and B will give you C and D, and adding formulas C and D will give you A and B.
Answer:
A, C and D
Explanation:
The impulse is defined as the product between the force (F) and the time of the collision (t):
Let's apply the formula to calculate the impulse for each situation:
A) 
B) 
C) 
D) 
We see that the situations in which the impulse is equal to 10 units are:
A, C and D
