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Eva8 [605]
3 years ago
13

What are tiny sacs at the end of the bronchioles filled with air called?

Physics
1 answer:
WARRIOR [948]3 years ago
7 0

Answer:

Alveoli

The bronchioles end in tiny air sacs called alveoli, where oxygen is transferred from the inhaled air to the blood.

Hope this helps :)

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The next closest star to Earth, Proxima Centuri, is 4.25 lightyears away. How far is that in meters?
lozanna [386]

Answer:

4.0208 x 10^16 meters

Explanation:

speed of light in m/s   *      # seconds in a year      * 4.25 years =

2.99792 x 10^8   *        3600*24*365.25  *     4.25 = 4.0208 x 10^16 m

8 0
2 years ago
Lava that is very runny probably
DENIUS [597]
A or B... I mean when lava is poured out to the surface, heat and soilica content may play a role... That's what I think sorry :(
5 0
3 years ago
Two 20.0 g ice cubes at − 20.0 ∘ C are placed into 285 g of water at 25.0 ∘ C. Assuming no energy is transferred to or from the
Lelechka [254]

Answer:

Ft = 17.48°C

Explanation:

Ft is the final temperature. However, ice absorbs heat during two process of melting and cooling and as such, there is no loss of heat to or from the surrounding hence by conservation of energy.

Therefore,

Heat absorbed by water of 20g = heat rejected by water of 265g.

So; M(ice)[C(ice) [(ΔT) + LH(ice) + C(water)(ΔT)] = C(water) M(water) (ΔT)

So, 20[(2.108) [0 - (-20)] + 333.5 + 4.187(Ft - 0)]] = (285)(4.187) (25 - Ft)

To get;

7513 + 83.74 Ft = 29832.4 - 1193.3 Ft

So factorizing, we get;

83.74 Ft + 1193.3 Ft = 29832.4 - 7513

So; 1277.04 Ft = 22319.4

So; Ft = 22319.4/1277.04 = 17.48°C

7 0
2 years ago
Which is less likely to be a reliable source of information, the webpage of a university or the webpage of a scientist who is tr
tatyana61 [14]

webpage of a scientist who is trying to sell a new invention

trying to dell = vested interest.

umiversity should be objective impartial

7 0
2 years ago
The depth of a pond is 1.5m. Calculate the pressure caused by the water at the bottom of the pond ?​?
zepelin [54]

Answer:

Area=1.5(1.5)=2.25m^2

Force of gravity=10N

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}

⟼Pressure=

Area

Force

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}

⟼Pressure=

2.25

10

\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}

⟼Pressure=4.4Pa

5 0
3 years ago
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