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hammer [34]
3 years ago
7

you are sitting in a cart at the top of a hill on a roller coaster. you have 10,500 j of gravitational potential energy. if your

current weight is 539N, how tall is the hill you are sitting on.
Physics
1 answer:
SSSSS [86.1K]3 years ago
8 0

Answer:

Height of sitting = 19.48 m

Explanation:

Gravitational potential energy = mgh

Current weight = 539 N

Weight = mg = 539 N

Mass x Acceleration = 539 N

Mass x 9.81 = 539

Mass = 54.94 kg

Gravitational potential energy = mgh = 10500 J

                     54.94 x 9.81 x h = 10500

                                h = 19.48 m

Height of sitting = 19.48 m

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3. What exerts a greater force on the table of 2 kg book lying flat or a 2 kg book on its
Darina [25.2K]

Answer:

A book on its side exerts a greater force.

Explanation:

Pressure = Force / Area

Assuming that 1kg = 10N

2kg = 20N

Area of book lying flat = 0.3m × 0.2m

                                     = 0.6m²

Pressure of book lying flat = 20N / 0.6m²

                                            = 30Pa (1 s.f.)

Area of book on its side = 0.2m × 0.05m

                                        = 0.01m²

Pressure of book on its side = 20N / 0.01m²

                                               = 2000Pa (1 s.f.)

Since 2000Pa (1 s.f.) > 30Pa (1 s.f.), a book on its side applies greater pressure than lying flat.

5 0
2 years ago
In a tape recorder, the tape is pulled past the read-and-write heads at a constant speed by the drive mechanism. Consider the re
Irina-Kira [14]

Answer:

Torque decreases .

Explanation:

The tape is pulled at constant speed , speed v is constant , so there is

v = ω r where ω is angular speed and r is radius , As radius decreases , angular speed ω increases , So there is angular acceleration .

Let it be α . Let I be moment of inertia of reel .

Reel is in the form of disc

I = 1/2 m r²

I x α = torque

1/2 m r² x α =  torque

As the reel is untapped , its mass decreases , r also decreases , so torques also decreases .

6 0
3 years ago
Which term describes information recorded during an experiment?
Mrac [35]
Data !
hope this helped <3
4 0
3 years ago
Read 2 more answers
A disc of mass m slides with negligible friction along a flat surface with a velocity v. The disc strikes a wall head-on and bou
qwelly [4]

Answer:

-v/2

Explanation:

Given that:

  • a disc of mass m
  • Collides with the wall going through a sliding motion on on the plane smooth surface.
  • Upon rebounding from the wall its kinetic energy becomes one-fourth of the initial kinetic energy before collision.

<u>We know, kinetic energy is given as:</u>

KE_i=\frac{1}{2}. m.v^2

consider this to be the initial kinetic energy of the body.

<u>Now after collision:</u>

KE_f=\frac{1}{4}\times KE_i

KE_f=\frac{1}{4} \times \frac{1}{2}\times m.v^2

Considering that the mass of the body remains constant before and after collision.

KE_f=\frac{1}{2}\times m.(\frac{v}{2})^2

Therefore the velocity of the body after collision will become half of the initial velocity but its direction is also reversed which can be denoted by a negative sign.

3 0
3 years ago
You buy a plastic dart gun, and being a clever physics student you decide to do a quick calculation to find its maximum horizont
Scilla [17]

Answer:

R_{max} = 51.84 m

Explanation:

When we shoot the dart upwards the time taken by the dart to go straight up and again come back is given as

t = 4.6 s

here we can say

\Delta y = 0 = v_i t + \frac{1}{2}at^2

0 = v_i t - \frac{1}{2}(9.8)t^2

put t = 4.6 s then we have

v_i = 22.54 s

Now in order to find the maximum range we can say

R = \frac{v^2 sin2\theta}{g}

so in order to have maximum range we can say

\theta = 45 degree

R_{max} = \frac{v^2}{g}

R_{max} = \frac{22.54^2}{9.8}

R_{max} = 51.84 m

5 0
3 years ago
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