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Charra [1.4K]
3 years ago
5

More than 200 years later, Albert A. Michelson sent a beam of light from a revolving mirror to a stationary mirror 15 km away. S

how that the time interval between light leaving and returning to the revolving mirror was 0.0001 s.
Physics
2 answers:
MrRissso [65]3 years ago
4 0

Explanation:

distance in meter= 15000 m

velocity of light v=3×10^8 m/s

time interval t= d/v

=\frac{15000}{ 3\times10^8}

= 0.00005 sec

This is the time for the path in one direction.  If you are looking for the time from the revolving mirror to the stationary mirror back to the revolving mirror, then it is twice the above value, which would be

2× 0.00005 =  0.0001 s

Aleks [24]3 years ago
3 0

Answer

given,

speed of light = 3 x 10⁸ m/s

distance of the mirror = 15 km

                                    = 15000 m

time interval between light leaving and returning = ?

we know,

distance = speed  x time

distance traveled by the light = 2 x 15000 = 30000 m

t = \dfrac{distance}{speed}

t = \dfrac{30000}{3 \times 10^8}

      t = 0.0001 s

hence, it is shown that the time interval is t = 0.0001 s

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3 years ago
A charged particle of mass m = 5.00g and charge q = -70.0μC moves horizontally to the right at a constant velocity of v = 30.0 k
pychu [463]

Answer:

The magnitude of the force, B = 5 Tesla, Up (North) direction

Explanation:

Magnetic force F= Eq where Electric field, E = 750 NC

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F = 750 ×  -7 ×10^{-5}

F = 0.0525

But F = qvB; B = \frac{F}{qv}

where B is the magnetic field

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B = 5.0 Teslas

The force on a negative charge is in exactly the opposite direction to that on a positive charge.

Hence the direction of the charge is up (North).

8 0
3 years ago
Read 2 more answers
Sound with a frequency of 1250 Hz leaves a room through a doorway with a width of 1.05 m.At what minimum angle relative to the c
kiruha [24]

Answer:

15.19°, 31.61°, 51.84°

Explanation:

We need to fin the angle for m=1,2,3

We know that the expression for wavelenght is,

\lambda = \frac{c}{f}

Substituting,

\lambda = \frac{344}{1250}

\lambda = 0.2752m

Once we have the wavelenght we can find the angle by the equation of the single slit difraction,

sin\theta = \frac{m \lambda}{W}

Where,

W is the width

m is the integer

\lambda the wavelenght

Re-arrange the expression,

\theta = sin^{-1} \frac{m\lambda}{W}

For m=1,

\theta = sin^{-1} \frac{1 (0.2752)}{1.05}= 15.19\°

For m=2,

\theta = sin^{-1} \frac{2 (0.2752)}{1.05}= 31.61\°

For m=3,

\theta = sin^{-1} \frac{3 (0.2752)}{1.05}= 51.84\°

<em>The angle of diffraction is directly proportional to the size of the wavelength.</em>

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2 years ago
The amount of time required for 2 successive wave crests to pass a fixed point is called wave ________.
mihalych1998 [28]
I believe this is known as wave period.
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7 0
2 years ago
If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed
beks73 [17]

Answer:

v = 5.9 x 10⁷ m/s

Explanation:

The kinetic energy of the electron in terms of potential difference is given as:

K.E = eV--------------- equation (1)

where,

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = Potential Difference = 9.9 KV = 9900 Volts

The kinetic energy in general is given as:

K.E = \frac{1}{2}mv^{2}\\--------- equation (2)

where,

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed of electron = ?

Therefore, comparing equation (1) and equation (2), we get:

\\\frac{1}{2}mv^{2} = eV\\\\\frac{1}{2}(9.1\ x\ 10^{-31}\ kg)v^{2} = (1.6\ x\ 10^{-19}\ C)(9900\ volts)\\\\v = \sqrt{34.81\ x\ 10^{14}} \\

<u>v = 5.9 x 10⁷ m/s</u>

8 0
3 years ago
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