More than 200 years later, Albert A. Michelson sent a beam of light from a revolving mirror to a stationary mirror 15 km away. S
2 answers:
Explanation:
distance in meter= 15000 m
velocity of light v=3×10^8 m/s
time interval t= d/v
=
= 0.00005 sec
This is the time for the path in one direction. If you are looking for the time from the revolving mirror to the stationary mirror back to the revolving mirror, then it is twice the above value, which would be
2× 0.00005 = 0.0001 s
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We can solve the problem by requiring the equilibrium of the forces and the equilibrium of torques.
1) Equilibrium of forces:
where
is the weight of the person
is the weight of the scaffold
Re-arranging, we can write the equation as
(1)
2) Equilibrium of torques:
where 3 m and 2 m are the distances of the forces from the center of mass of the scaffold.
Using
and replacing T1 with (1), we find
from which we find
And then, substituting T2 into (1), we find
1) Equilibrium of forces:
where
Re-arranging, we can write the equation as
2) Equilibrium of torques:
where 3 m and 2 m are the distances of the forces from the center of mass of the scaffold.
Using
from which we find
And then, substituting T2 into (1), we find