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2 years ago

Select the PREDICATE ADJECTIVE(S) (if one or more is present).

Chemistry

1 answer:

creativ13 [48]2 years ago

8 0

<u>Answer:</u> There is no predicate adjective in the sentence.

<u>Explanation:</u>

Predicate adjective is defined as an adjective that follows the linking verb and modifies the subject of the linking verb.

For Example:

The shoes look expensive.

In this sentence, the shoes are the subject, 'look' is the linking verb and 'expensive' is the predicate adjective.

The predicate adjective modified the subject.

In the given sentence,

'Five' is a common noun, 'cookies' is the subject, 'are' is the helping verb, 'on' is the preposition, 'the' is an article and 'table' is a countable noun.

Hence, there is no linking verb and therefore, this sentence has no predicate adjective.

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Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p

UNO [17]

Answer : The equilibrium constant $K_c$ for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of $Br_2$ .

$\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}$

$\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M$

Now we have to calculate the dissociated concentration of $Br_2$ .

The balanced equilibrium reaction is,

$Br_2(g)\rightleftharpoons 2Br(aq)$

Initial conc. 1.731 M 0

At eqm. conc. (1.731-x) (2x) M

As we are given,

The percent of dissociation of $Br_2$ = $\alpha$ = 1.2 %

So, the dissociate concentration of $Br_2$ = $C\alpha=1.731M\times \frac{1.2}{100}=0.2077M$

The value of x = 0.2077 M

Now we have to calculate the concentration of $Br_2\text{ and }Br$ at equilibrium.

Concentration of $Br_2$ = 1.731 - x = 1.731 - 0.2077 = 1.5233 M

Concentration of $Br$ = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

$K_c=\frac{[Br]^2}{[Br_2]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.4154)^2}{1.5233}=0.1133$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.1133

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2 years ago

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marusya05 [52]

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3 years ago

Which of the follow describes what happpens to the kinetic energy of water when it changes from the solid state to a liquid stat

Anestetic [448]

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Kinetic energy increases.

Explanation:

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From greatest to lowest kinetic energy:

gas, liquid, solid

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3 years ago

One molecule of glucose makes 36 molecules of atp how many molecules of glucose are needed to make 1800 molecules of atp

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What are the typical properties of covalent substances ?

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