Nitrogen in this compound has 2 atoms. 2 multiplied by its mass, 14.007, equals 28.014. Divide 28.014 by the molar mass of calcium nitrate: 28.014/164 = 0.17081. Multiply this by 100 to achieve its percentage: 0.17081 x 100 = 17.08%
<h2>
Answer:</h2>
% Composition of elements:
- Magnesium = 75%
- Oxygen = 25%
Atomic mass of given elements:
- Magnesium = 24 g
- Oxygen = 16 g
Now, divide % composition by Atomic mass:
Simplest Ratio:
Empirical Formula:
The formula you need is: heat= specific heat x mass x ΔT
specific heat= 0.46 j/g-C
mass= 100.0 grams
ΔT= 40.2 - 15.0= 25.2C
heat= (0.46) x (100.0) x (25.2)= 1159.2 joules or 1200 joules (rounded off)
Answer:
HCOOH(aq) + OH-(aq) —> HCOO-(aq) + H2O(l)
Explanation:
HCOOH is a weak acid and so will not ionised completely in solution.
KOH is a strong base and will ionised completely as shown below
KOH(aq) –> K+(aq) + OH-(aq)
The overall reaction can be written as follow:
HCOOH(aq) + K+(aq) + OH-(aq) —> HCOO-(aq) + K+(aq) + H2O(l)
Cancel out the K+ to obtain the net ionic equation as shown below
HCOOH(aq) + OH-(aq) —> HCOO-(aq) + H2O(l)
Answer:
4moles
Explanation:
2moles produces 2moles of H2
then 4moles (72g) produces 8 grams H2
