Complete ionic:
Cu(aq) + 2Cl(aq) + 8O(aq) + 2Na(aq) + C(aq) + 3O(aq) = CaCO3(s) + 2Na(aq) + Cl(aq) + 4O(aq)
Net ionic:
Cu(aq) + Cl(aq) + 4O(aq) + 2Na(aq) + C(aq) + 3O(aq) = CaCO3(s)
So write everything out as IF it will dissociate in water. So everything that is aq splits but solid just floats to the bottom of the mixture. Cancel what you can (in this case the two from the ClO4 on the left of the equation cancels with the ClO4 from the right) and the 2Na cancels. Then, write out the whole solution and you are done!
I think it’s the third option
Answer:
The answer to your question is below
Explanation:
11. Alkali metals
12. Halogens
13. Transition metals
14. Halogens
15. Noble gases
16. Alkaline earth metals
17. Transition metals
18. Alkaline earth metals
19. Transition metals
20. Alkali metals
21.- Periods
22.- Calcium
23.- Iodine, I
24.- A. atomic number
Hey there,
Answer:
4 valence electrons.
Hope this helps :D
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